Also on the Green die, do you mean 2 6 2 6 2 6? You only have two 6s

but I think you should do your own homework.

I know the answer but will keep it to myself for now.

Here is a pdf link to help answer these type of questions.

http://www.madandmoonly.com/doctormatt/mathematics/dice1.pdf

From: Matthew Conroy's page of mathematics

http://www.madandmoonly.com/doctormatt/mathematics/mathematics.htm

Looks to be similar to question #25

current version July 1, 2012

Quote:anaid23Blue dice has 1 1 1 1 7 7

yellow dice has 4 4 4 4 4 4

green dice has 2 6 2 6 2 2

orange dice has 3 5 3 5 3 5

Four dice with varying numbers on each face. You and three friends will play a simple game where you will each roll one of the dice and the highest number wins. You get first pick from the dice.

Question: Which die should you choose in order to maximize your chance of winning?

I believe the yellow and orange dice have same odds of winning/being the best choice of dice.

green has four 2s and two 6s

4 die, all 6 sided are rolled. This means there are 1296 combinations that can be rolled. Obviously Blue dice win 432 times, since two of their sides are higher than every other die roll (2x6x6x6). The other colors all win 288 times each, therefore, the answer is :

BLUE

Odds on who wins :

blue 2-1

yellow 7-2

green 7-2

orange 7-2

If we put a 5% vig on the prop, we would offer : blue +185, yellow +327, green +327, orange +327

Quote:shakhtarOdds on who wins :

blue 2-1

yellow 7-2

green 7-2

orange 7-2

Isn't 7:2 a higher probability than 2:1?

Quote:tuppIsn't 7:2 a higher probability than 2:1?

no. 2-1 equals a 33.33% chance of occurring, 7-2 equals a 22.22% chance of occurring

odds are a reflection of the chances of something occurring vs. the chances of something not occurring.

I'm assuming you don't do too much gambling, and by the oft chance that you do, you should probably find another hobby.

Quote:shakhtarno. 2-1 equals a 33.33% chance of occurring, 7-2 equals a 22.22% chance of occurring

odds are a reflection of the chances of something occurring vs. the chances of something not occurring.

I'm assuming you don't do too much gambling, and by the oft chance that you do, you should probably find another hobby.

No need for the the personal comments.

I do not wish to seem pedantic nor start a semantics argument. However, for the ratios to match "the chances of something occurring vs. the chances of something not occurring," would not the ratios actually have to be inverted, to 1:2 and 2:7, respectively?

Furthermore, even if we invert the ratios, they do not match the percentages given. 1/2≠33.33%, and, likewise, 2/7≠22.22%.

On the other hand the percentages do match another ratio: the chances of something occurring vs. the total possibilities. So, 1/(1+2)=33.33%, and 2/(2+7)=22.22%.