August 20th, 2013 at 10:33:21 AM
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I'm studying Mike's exposition of craps probability figuring, on:
http://www.mathproblems.info/gam470/games/craps/notes-craps.html
and am stuck at the bottom of the (Craps) article. Where's he getting the 3/7 (of money bet) fraction he's using for figuring allowable odds multiples vig calc's? Can't figure it out.
Thx in advance for anyone's help.
Andy Eppink
http://www.mathproblems.info/gam470/games/craps/notes-craps.html
and am stuck at the bottom of the (Craps) article. Where's he getting the 3/7 (of money bet) fraction he's using for figuring allowable odds multiples vig calc's? Can't figure it out.
Thx in advance for anyone's help.
Andy Eppink
August 20th, 2013 at 11:10:22 AM
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The average line bet is going to be 1, or 3/3, while the average odds bet is 4/3. Add them together and you get 7/3 average total bet.
Now to find out how much of that total is the line bet, divide the line bet by the total, or 1 / (7/3) = 3/7
Now to find out how much of that total is the line bet, divide the line bet by the total, or 1 / (7/3) = 3/7
August 20th, 2013 at 11:16:06 AM
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Thx. Overlooking the obvious. Again. I'm good at it.
August 20th, 2013 at 11:21:30 AM
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1 / (7/3) is also equal toQuote: wudgedThe average line bet is going to be 1, or 3/3, while the average odds bet is 4/3. Add them together and you get 7/3 average total bet.
Now to find out how much of that total is the line bet, divide the line bet by the total, or 1 / (7/3) = 3/7
1 * (3/7)
(instead of dividing by 7/3 we can also multiply by the inverse: 3/7
many will find this method easier to do while driving down the highway)
winsome johnny (not Win some johnny)