I had some info from wizardofodds.com Three Card Poker and was wondering IF it is at all possible to shift the odds to the players advantage if always playing the bet (never folding).
On that webpage, the 3rd comment down is answered "The house edge lies in the rule that if the player folds he loses, even if the dealer doesn’t qualify."
So what if the player never folds, even with Q,6,4 or less?
If a player bets blind, are the odds of the players cards vs dealer cards a 50/50 split? Then throw in the rule that a dealer must qualify, does this not take the player from a 50/50 to a higher advantage as the dealer may not qualify?
What are the odds of a dealer qualifying? And from there, what are the odds of the dealer winning the hand.
It has always been said that Three Card Poker has a house advantage based on if the Player bets. So why not reverse the rules on the house. Player is always in, House now must decide (qualify) on playing on.
On a $5 table, you would really be playing $5 Ante $5 Bet. So $10. but if dealer does not qualify, you only make $5. Regardless of te amount you make, the question remains, what are odds of winning if you always go in?
(No pair plus. Don't even care for this bet so lets keep it out of the equation)
Quote: QikGT
On a $5 table, you would really be playing $5 Ante $5 Bet. So $10. but if dealer does not qualify, you only make $5. Regardless of te amount you make, the question remains, what are odds of winning if you always go in?
(No pair plus. Don't even care for this bet so lets keep it out of the equation)
You answered your own question right there. You do have a 50/50 chance of having a better hand than the dealer. But you only win even money on that 50/50 chance when the dealer has a Q or better. All the times you have a better hand and the dealer DOESN'T have a Q, you only win 5 rather than 10. But if the dealer beats you, you lose 10. This disadvantage is bigger than the advantage you get of winning 5 by risking 10 when you have a WORSE hand but the dealer doesn't have a Q. From the Wizards page:
https://wizardofodds.com/games/three-card-poker/
Raising on everything, or playing blind, results in a house edge of7.65%.
This doesn't matter about how much the bet is, or how much profit is made. So regardless of the bet amount, and regardless of the profit margin,
Take one hand, 3 cards for player, 3 cards for dealer, but dealer can't play if he doesn't qualify. What is the house/player edge? It must be in the favor of the player at this point as to who will win.
Quote: QikGT
What is the house/player edge? It must be in the favor of the player at this point as to who will win.
No, it isn't. Really, if that were the case, why would people have taken the time to determine that it only makes sense to stay in with Q-6-4 or higher?
Regarding the Pair Plus, pay attention to the pay table. if it is 6-4-3-1, it isn't a bad bet, with an edge/eor of 2.38%.
My question is, regardless of payouts or bet amounts, if a player was given 3 cards, and the dealer was given 3 cards, what are the chances of the player winning?
Then you can throw into the equation the fact that the dealer can ONLY winif they qualify with a Q or higher.
So in a single deck game, where 52 cards are used, and 3 are given to the player, 3 to the dealer, dealer has to qualify, WHAT ARE THE PLAYERS ODDS?
edit: the house advantage aslo stems from the Customer plays first... an important concept. Especially playing blind or in your example of deal 3 cards per opponent. Since you don;t know the contents of the opponent's hand, it becomes difficult to wager the outcome... your Straight-Flush might be beaten by Triples... your 10-6-5 might beat your opponent's 8-3-2. Going first, or wagering first is a disadvantage, because of the lack of information.
To confirm, one hand, player 3 cards, dealer 3 cards, dealer must qualify. What are players odds of winning?
(Part of this question needs the answer of odds dealer will even qualify. I'd like to know that too)
So, first off, can anyone else confirm this? (Just like to double and triple check things)
And if it is 54.5%, does that mean the player has a 4.5% edge over the dealer, to WIN?
Quote: QikGTGive the man a medal, he CAN do math AND read. Thanks.
So, first off, can anyone else confirm this? (Just like to double and triple check things)
And if it is 54.5%, does that mean the player has a 4.5% edge over the dealer, to WIN?
Qik- as I pointed out earlier, the members of this site are happy to answer questions that are clear, and also, as sometimes it might require a bit of work on their part, might want to know WHY you are asking. The phrase 'edge over the dealer' is ambiguous. Let me give you an example. If I went to a roulette table and put $10 on numbers 1 - 33, I would be risking $330, and more often than not I'd win. But I never would have had an 'edge over the dealer' in my mind. I knew I'd be more likely to win a small amount than lose the big amount, but I never had an 'edge'. Another example would be video poker. You will never come close to winning half of your bets, but because some wins are greater than even money, even winning 25% of the time you 'might' have an edge over the dealer, depending on paytable and game.
Quote: QikGTGive the man a medal, he CAN do math AND read. Thanks.
So, first off, can anyone else confirm this? (Just like to double and triple check things)
And if it is 54.5%, does that mean the player has a 4.5% edge over the dealer, to WIN?
I'm still really confused by what you want to know. Yes, you'll win 54.5% of the time. But some of the wins will be 2 units (when the dealer qualifies), and some of the wins will be 1 unit (when the dealer does not qualify). All of the losses will be 2 units. This is NOT a winning strategy for the player.
When would it be realistic to play this game blind and still have a strong edge over the house (without any knowledge of the dealer's cards)?
Hint: the answer is contained within this thread.
That's why I didn't bother trying to figure it out.
Au contraire. Let me assure you that I have little interest in problems like this without practical application.Quote: FinsRuleLet me help clarify. He's asking a question that the answer has no practical application whatsoever.
Assume adequate shuffling (e.g. a Shuffle Master iDeal).Quote: FinsRuleIf the cards are not shuffled correctly after each hand. Got it.
I won`t post the details but lets just say the dealer didn`t know the rules of the game.
(a) looking and playing odds against (i.e. folding bad hands, losing 1; only playing good hands and hopefully winning R+1)
(b) blind and playing odds on (i.e. good/bad hands win 1 if dealer not qualify, bad hands lose R+1).
The difference is quite easy as with good hands you'd always play, so the only case to worry about is bad hands.
Ignoring when your Q43 beats Q32 (you actually gain +2 if you play)....
(a) FOLD - You make the correct decision if the dealer qualifies 70% and the wrong if he doesn't 30%. Thus you gain the "raise" you didn't make 70% of the time, and 30% of the time it cost you two (you lost 1 rather than winning 1). 70% +1 vs 30% -2
(b) PLAY - The reverse applies, if the dealer qualifies you lose an extra one, if the dealer doesn't you win rather than lose. 70% -1 vs 30% +2.
Thus you are better to FOLD bad hands and take the -1 rather than have a 30% chance of winning 1 and 70% chance of losing 2.
fwiw In 5-card poker the percentages as much closer (except A K) and with AK you are risking +1 vs -3 at about 49% 51% rather than -1.
Actual values are about 30.4% 69.6%; and for 5-card close when have AK yourself, otherwise is nearly 45.7% and even worse if the dealer has A or K.
Can't believe NO ONE can read.
Instead, they all complicate this situation with thinking of their own, so I wil start it again....let's see if ANYONE can follow along.
FOR THE SAKE OF ME KNOWING, AND NO OTHER REASON, Not for a strategy, not for profit, simply as 'what are the percentage odds', all I ask is.......
....and lets get ready for it....
.....only take these factors please. If a 52 card deck is played, and 3 cards are given to player A, and 3 cards are given to player B, what are the odds of player A winning (all I want to know, is the winning factor) if player B can not play if he holds a J high or lower?
Don't bother responding if you are NOT going to respond with the edge % of player A & player B. And don't bother explaining the payout , because that is not what this question is about.
Thanks, happy gamblin'.
Quote: QikGT\was wondering IF it is at all possible to shift the odds to the players advantage if always playing the bet (never folding).
So what if the player never folds, even with Q,6,4 or less?
Then throw in the rule that a dealer must qualify, does this not take the player from a 50/50 to a higher advantage as the dealer may not qualify?
What are the odds of a dealer qualifying? And from there, what are the odds of the dealer winning the hand.
So why not reverse the rules on the house. Player is always in, House now must decide (qualify) on playing on.
Regardless of te amount you make, the question remains, what are odds of winning if you always go in?
You say we can't read, yet you asked several questions OTHER than "what is the percentage of wins if you play blind" That led most of us to believe you wanted some help about why playing blind was a bad idea. But clearly you just want justification that your system will work. OK, here it is: You will win about 60% of the time. However, like the roulette bet of playing 2 out of 3 columns, you will win less on those 60% than you will lose on the 40%, making it better to fold the worst of your losers (Q64 and under). If you'd rather not fold, no problem. You'll win about 3 of every 5 hands, and you'll be giving the casino about 5 cents more of every dollar you bet than you would if you played smartly. But yes, you will win more hands.
Quote: QikGT
Don't bother responding if you are NOT going to respond with the edge % of player A & player B. And don't bother explaining the payout , because that is not what this question is about.
Uhoh, here I am responding without telling you the edge % of player A. Geez, lighten up.
Quote: SOOPOOIm ok at math. Captain of my high school math team. ( I got to wear the coveted number pi). Perfect 800 on math achievement test. 4th place in NYC math competition. Sooooo.... if the 70% figure is correct.... the dealer wont qualify 30% of the time. So 30% of the time a hand will be j high or worse. So 9% of the time you will both have j high or worse (an approximation because if you know 3 cards are out and are j high or worse then the remaining 49 cards a re 'rich' in higher cards). And half of the time you both don't 'qualify' you would have had a worse hand than the dealer, but will now win because the dealer is forfeiting. So if 70% is correct, then you will win approximately 54.5% of the time.
Can't YOU read? This is the answer to your question. approximately 54.5%
But seriously, no one here works for you. You are asking people a FAVOR to help you out. I can assure you berating the forum members who do not answer exactly as you like will not engender future positive responses to your questions. I already told you, if you give us a clue as to WHY you are asking a question it is more likely we can help you out.
The dealer qualifies on 69.5% of hands. You will win about 54.49% of the time. That doesn't matter though because you are risking 2 units to win 1. That's where the house advantage comes in. On average you will lose 0.06639 units (HA 6.639%). Note that I am assuming two independent decks.
The fact is that when you raise blindly with a non qualified hand (J high or less), you will on average, lose 1.08778 units. That's because you win 1 unit 6,720 / 22,100 of the time but lose 2 units 15,380 22,100 of the time. When you throw in an unqualified hand, you lose 1 unit.
On average then, you will lose an extra unit about every twelve unqualified hands. On a 4 hour 3 card session, you will see about 120 hands. On average, you will have 36 unqualified hands which will cost you, on average 3 units by using this betting strategy. On a single session then, you are probably within the variance to believe that betting blind is helpful. There will be a few times when the dealer flops more than the average non-qualifiers leading you to believe that betting blind is the right way to go. And perhaps, for that session, it would have been. But hindsight is 20/20.
There is a way... and its NOT legal.
Eliminating this phrase from my vocabulary has had a profound effect on my wallet.Quote: 98ClubsYou can only...
1) Never play PairPlus (even at the most favorable pay table)
2) Play for a raise if you have a Q-6-4 or better, otherwise fold.
Is this correct?
2) Yup, that's it.
if you do get it, I agree with PopCan. My last chance to play, I debated about this quite a bit. I decided under no circumstances sit there and play for more than a few hands. I would play the PairPlus only and not the other! but when it came down to my chances the paytable was not the favorable one, and I wound up not playing 3 card poker at all.
The pairplus may be a sucker bet, but at least you can win 40x your bet. If I'm playing an even money game to get a good bet, I'm playing craps, bj, bac. If I'm playing an even money game to let my money last I'm playing Pai Gow Tiles/Poker. TCP doesn't really have any positives.
I will on occasion play 3CP if i see a sloppy dealer.
I love it when people get pissy with me for not playing the pair plus.
I keep count of all my won/lost hand counts and can instantly tell them how far DOWN
I would still be even if I had been playing the pair plus.
It usually shuts them up.
Sometimes when someone busts out of the table I like to ask
"how did that pair plus bet work out for you?"
Apply to Ante/Raise (as above)
Apply to Pairs Plus (using 1.000 as ave. bet)
If Ante = Pair Plus the lesser "donation" to the house can be the Pair Plus alone, but not if using the stingy 7% rate.
Which is precisely why the Pair Plus bet stinks.
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