The problem i have is although i know that mathematically the odds of an outcome remain the same no matter what has happened before, the odds of 18 unique numbers hitting in 18 consecutive spins is not 1/37 and the odds of hitting 37 unique numbers in 37 spins is as near to impossible as it can get.
I am not all that intelligent and my judgement may be distorted from wanting to find a way to beat the casino and make millions but surely if it is almost impossible for 37 numbers to hit in 37 spins. A number that has already hit has odds lower than 1/37 of hitting again in 37 spins simply because not all 37 numbers will hit.
Really my only question is what is the most number of unique numbers anyone has seen consecutively and how often. for example I believe the most unique numbers i have seen is 17 or 18 and i have probably seen that 5 or 6 times in thousands and thousands of spins. the most i have heard of anyone seeing is 20 if anyone has seen more than it would be great if you could comment.
If you are interested the system is an increment betting system. first you need to watch 8 spins and keep your fingers crossed you dont see a repeat. then bet 1 unit on each of the 8 numbers that hit, then 2 units on the 9 numbers hit and so on you do not have to double up every time, but to make it to the 20th spin you will need 8973 units and your average return will only be around 23 units. so your risking a lot for a little. it will take 384 wins to cover your bankroll and also a lot of time as 50% of the time you will see a repeat before the 8th spin. i have tried a lot of systems and on thing i have learnt is you lose. Hopefully this system will see you win more than 384 times before you lose
Quote: chaosrevoltHi, I have been working on a system that involves repeating numbers. To be honest i have tried every single system i could research or conjure up on my own and all have ultimately failed but despite that and every mathematician telling me roulette is impossible to beat and fully understanding the gamblers fallacy there is one thing that i just cant get past.
The problem i have is although i know that mathematically the odds of an outcome remain the same no matter what has happened before, the odds of 18 unique numbers hitting in 18 consecutive spins is not 1/37 and the odds of hitting 37 unique numbers in 37 spins is as near to impossible as it can get.
I am not all that intelligent and my judgement may be distorted from wanting to find a way to beat the casino and make millions but surely if it is almost impossible for 37 numbers to hit in 37 spins. A number that has already hit has odds lower than 1/37 of hitting again in 37 spins simply because not all 37 numbers will hit.
Really my only question is what is the most number of unique numbers anyone has seen consecutively and how often. for example I believe the most unique numbers i have seen is 17 or 18 and i have probably seen that 5 or 6 times in thousands and thousands of spins. the most i have heard of anyone seeing is 20 if anyone has seen more than it would be great if you could comment.
If you are interested the system is an increment betting system. first you need to watch 8 spins and keep your fingers crossed you dont see a repeat. then bet 1 unit on each of the 8 numbers that hit, then 2 units on the 9 numbers hit and so on you do not have to double up every time, but to make it to the 20th spin you will need 8973 units and your average return will only be around 23 units. so your risking a lot for a little. it will take 384 wins to cover your bankroll and also a lot of time as 50% of the time you will see a repeat before the 8th spin. i have tried a lot of systems and on thing i have learnt is you lose. Hopefully this system will see you win more than 384 times before you lose
Hi New member. Welcome.
Just research the basics. On American roulette, over the lifetime of ANY system, you should expect to lose 2/38 x Total amount staked.
I.E. Your system might be amusing, but it is financially worthless to the EXACT same extent as EVERY OTHER SYSTEM.
It's easy to fall into a trap along the lines of "since red has come up 18 times in a row, there must be a higher probability of black coming up next", and that thinking sorta makes sense at face value, but that's why it's called a fallacy. The wheel has no memory, period, point blank. Past events, no matter how improbable, cannot change the probability of future events.
The only way to beat roulette that I'm aware of is by finding a bias wheel (good luck), and kinda sorta maybe but probably not wheel clocking (also...good luck). But you shouldn't waste your time with either. If you want to find a beatable game, try BlackJack or Full Pay DDB/DW video poker.
P(n) = Sum (37-n)/37
So the odds of seeing all 37 come out uniquely is 36/37 * 35/37 * 34/37 * 33/37 * 32/37 * ... 1/37 = .00000000000000130399.
Once again, for all readers, previous spins have no effect on future spins. Your system will result in a 2.71% house advantage, so if you are betting 8 units, you will start getting past the point of no return after 6 non-winning spins assuming you increasing by one unit and you start your next run next time you see 8 uniques.
Win 28 units 21.62% (Bet 1 unit on 8 spots) (35 - 7)
Win 46 units 19.06% (Bet 2 units on 9 spots = (70-16) - 8 from the previous)
Win 52 units 16.03% (Bet 3 units on 10 spots = (105 - 27) - 8 - 18 from the previous spins)
Win 44 units 12.87% (Bet 4 units on 11 spots = 140 - 40 - 30 - 18 - 8 from previous spins)
Win 20 units 9.86% (...)
Lose 22 units 7.22% (...)
Lose 238 units 13.33% (I give up!)
Net house advantage = 2.52 units on the progression. Which go figure is 1/37 * the average bet!!!
So unless you think the wheel is truly biased you might as well bet on random numbers.
But whatever floats your boat.
1 2 3 4 5 6 7 8 9 10
or
4 4 4 4 4 4 4 4 4 4
or
7 2 5 9 4 8 6 3 1 10
are all exactly the same. It may seem that getting ten fours in a row is less likely than 7 2 5 9 4 8 6 3 1 10; but it isn't. The fact that these seem to suggest a pattern to the human brain, which likes to see patterns, does not affect randomness, where there are no patterns. None of these sets suggests what the eleventh roll will be.
I am aware of the basics. i only ever play european roulette as the odds are slightly better.
I have used lots of different systems and lost however the only reason they dont work is the table limit. if there was no table limit and a gambler had infinite amount f money they would all work. I.E wait for 36 numbers to hit then bet on the remaining one. I tripled my money using that system but the return for effort/time/risk wasnt worth it. i may have just been lucky as i could have put all my money on the first 12 and tripled my money. However the 37th number will eventually hit its a question of when not if. Another system i used had me on average win 33 times to every loss over hundreds of plays but that was only ever enough to break even, a complete waste of time. I am not claiming that the system will be profitable. As with all gambling it is exactly that a gamble. you could lose twice in a row there is nothing to stop that but its simply trying to improve the odds. As i mentioned i have personally never seen more than 18 unique numbers in a row. so if i had played this system from my very first spin i would be a rich man. the simple fact is you dont just have to win but it has to be worth winning. if the system i used to break even had of won 34 times to every loss over the hundreds of spins i would have been +3units but it simply took to long to earn those 3 units to be worth doing. the system i wrote about is untested (by myself) and although i have never seen 20 repeats if (best case) it did happen after 384 spin you would have spent at least a couple of days to win 23 units. i think the casinos are safe.
Quote: QFITSuppose you have ten possible numbers with equal odds of appearance and ten rolls. The odds that you will get:
1 2 3 4 5 6 7 8 9 10
or
4 4 4 4 4 4 4 4 4 4
or
7 2 5 9 4 8 6 3 1 10
are all exactly the same. It may seem that getting ten fours in a row is less likely than 7 2 5 9 4 8 6 3 1 10; but it isn't. The fact that these seem to suggest a pattern to the human brain, which likes to see patterns, does not affect randomness, where there are no patterns. None of these sets suggests what the eleventh roll will be.
Thats my exact point even thou mathematically the odds are the same in reality it doesnt work like that you are much more likely to get a repeat than see all 10 numbers
Quote: QFITIf the player had an infinite amount of money, he could never win because he could never increase his bankroll.
and why would he need to gamble?
You're welcome.Quote: chaosrevoltThanks for the welcome.
and I bet you know that EVERY SPIN has the same house advantageQuote:I am aware of the basics. i only ever play european roulette as the odds are slightly better.
No. Actually: You could never increase your infinite bankroll. DON'T try to argue that, as to do so would reveal you to be an unwanted troll.Quote:I have used lots of different systems and lost however the only reason they dont work is the table limit. if there was no table limit and a gambler had infinite amount f money they would all work.
Quote:. . .I tripled my money using that system but the return for effort/time/risk wasnt worth it. i may have just been lucky
Yes. you had perfectly ordinary luck. The probability of that success was almost 33%
See https://wizardofvegas.com/member/oncedear/blog/2/#post1370
They all are. EXACTLY EVENLY WORTHLESS.Quote:Another system . . . a complete waste of time.
What part of 'The house edge is a constant don't you understand? The odds. What odds? The odds of winning per session, which can be increased vastly and easily. Or the odds of increasing your bankroll by exactly 100%. You can't alter those one jot.Quote:. . . but its simply trying to improve the odds.
1 1 3 5 5 7 2 2 9 10
is just as likely as...
1 2 3 4 5 6 7 8 9 10
And even more so,Quote: IbeatyouracesThis....
1 1 3 5 5 7 2 2 9 10
is just as likely as...
1 2 3 4 5 6 7 8 9 10
This....
0,0,0,0,0,0,0,0,0,0,1,1,3,5,5,7,2,2,9,10
is just as likely as...
[Insert any conceivable 20 spins]
Quote: chaosrevoltas i said im not that intelligent. i would bet everything even my lungs and my kidneys u cant get 1 2 3 4 5 6 7 8 9 10 to come out which means a repeat must be more likely whatever anyone says.
Probably because there are more combinations of ten numbers where you'll see the same number at least twice. It doesn't change the fact that you cannot predict these outcomes.
Quote: chaosrevoltThats my exact point even thou mathematically the odds are the same in reality it doesnt work like that you are much more likely to get a repeat than see all 10 numbers
And each of the about 2,756 (assuming my abacus is working and that last glass of wine hasn't hit yet) sets with a repeat would be exactly as likely as a set with no repeats. The point is that any set, whether there exist repeats or not, is exactly as likely. 1 2 3 4 5 9 9 9 9 9 is exactly as likely as 1 2 3 4 5 6 7 8 9 10.
(Wish I'd picked a smaller number.:))
Quote: IbeatyouracesProbably because there are more combinations of ten numbers where you'll see the same number at least twice. It doesn't change the fact that you cannot predict these outcomes.
you just bet on ones that come out one will repeat because as u say there are more combinations where 1 2 3 4 5 6 7 8 9 10 doesnt occur. this improves your odds surely and if you double up everytime u will win???
1 1 1
1 1 2
1 1 3
1 2 1
1 2 2
1 2 3
1 3 1
1 3 2
1 3 3
2 1 1
2 1 2
2 1 3
2 2 1
2 2 2
2 2 3
2 3 1
2 3 2
2 3 3
3 1 1
3 1 2
3 1 3
3 2 1
3 2 2
3 2 3
3 3 1
3 3 2
3 3 3
As you see, there are 27 possible ways these numbers come out and only 6 don't have a repeater. Therefore 21 DO repeat. The point is, each of these 27 combos are equally likely and you cannot predict which one will show up.
I've been hard on you so let me give you this: you need to think about how common your approach is. One billion gamblers before you have tried to find some angle in the same way you are trying. You have to realize no one has found success and ask why.
Quote: IbeatyouracesUse the numbers (1, 2, 3) and here are the combos:
1 1 1
1 1 2
1 1 3
1 2 1
1 2 2
1 2 3
1 3 1
1 3 2
1 3 3
2 1 1
2 1 2
2 1 3
2 2 1
2 2 2
2 2 3
2 3 1
2 3 2
2 3 3
3 1 1
3 1 2
3 1 3
3 2 1
3 2 2
3 2 3
3 3 1
3 3 2
3 3 3
As you see, there are 27 possible ways these numbers come out and only 6 don't have a repeater. Therefore 21 DO repeat. The point is, each of these 27 combos are equally likely and you cannot predict which one will show up.
im not saying you can predict anything im saying your odds will improve in this case 1/9 that there wont be a repeat as opposed to 1/3. i could be completly wrong. has anyone ever seen more than 20 numbers without repeat?
Go away and calculate exactly the house edge on your proposition.
Quote: chaosrevoltim not saying you can predict anything im saying your odds will improve in this case 1/9 that there wont be a repeat as opposed to 1/3. i could be completly wrong. has anyone ever seen more than 20 numbers without repeat?
The past doesn't predict the future. Whether you do or don't see one, it won't help you.
Quote: odiousgambityou are displaying "invincible ignorance" which you can look up with google or wikipedia - it suggests trolling so I would take a breath and go back and read and defeat my ignorance if you are for real
I've been hard on you so let me give you this: you need to think about how common your approach is. One billion gamblers before you have tried to find some angle in the same way you are trying. You have to realize no one has found success and ask why.
"invicible ignorance" i like that. im not trying to be anything. im not trying to prove a point and im telling anyone how it is or what they should do. i am fully aware no one has ever beat roulette and that it is impossible to beat the casino. no matter how much "invincible ignorance" i choose to display but is this or is this not a forum about betting systems. Try the syste you might win you will probably lose. i dont have much else to do other than write on here and endlessly spin a roulette wheel. looking for things that might increase your chance of winning. i know its a crappy life. i didnt force u to read this so please dont call me a troll. if a man had infinite money he would always win but would he really need to? without being offensive i am actually intrested to know how he couldnt increase his bankroll if that was the case
Quote: OnceDearOh to hell with this nonsense!!!!
Go away and calculate exactly the house edge on your proposition.
i know why they have the zero and only pay 1/35. i know what that is. the odds are against u without doubt. i was simply asking a question not one person has giving me an answer
But most of us on the forum realize that no matter what happens even if they see 1-2-3-4-5-1-2-3-4-5-1-2-3-4-5-1-2-3-4-5 it's an unusual pattern but just as likely as 11, 36, 5, 16, 18, 35, 14, 18, 1, 29, 5, 19. 0, 20, 32, 34, 24,10, 35.
So, none of has seen it. Doesn't mean that it doesn't happen, because no one is looking for it.
25Quote: chaosrevolt<snip>
Really my only question is what is the most number of unique numbers anyone has seen consecutively and how often.
and 2 times over thousands of spins.
was a big loser betting against it (not by me of course)
also seen 20 and 21 more than 2 (can't recall how many)
I think this was posted B4 using BruceZ R code
unique prob up to 20 spins for 37 slot wheel
(Hi BruceZ)
> draw.unique = function(u,d,n,digits=10) {
+ require(Rmpfr)
+ ulen = length(u)
+ umax = u[ulen]
+ bits = ceiling(lchoose(umax,umax%/%2)/log(2)+ d*log2(n))
+ p = rep(0,ulen)
+ for (i in 1:ulen) {
+ j = 0:(u-1)
+ a = chooseZ(u,j)
+ b = mpfr(u-j,bits)
+ N = mpfr(n,bits)
+ p = as.double(choose(n,u)/N^d * sum((-1)^j * a*b^d))
+ }
+ p = as.matrix(p)
+ rownames(p) = paste("u=",u," ",sep="")
+ colnames(p) = "Prob"
+ cat("\n")
+ print(formatC(p,digits),quote=FALSE)
+ }
> draw.unique(1:1,1,37)
Prob
u=1 1
> draw.unique(1:2,2,37)
Prob
u=1 0.02702331543
u=2 0.9729003906
> draw.unique(1:3,3,37)
Prob
u=1 0.000730458647
u=2 0.0788898468
u=3 0.9203796387
> draw.unique(1:4,4,37)
Prob
u=1 1.974216684e-05
u=2 0.004975026299
u=3 0.149250783
u=4 0.8457544148
> draw.unique(1:5,5,37)
Prob
u=1 5.335720887e-07
u=2 0.0002881289281
u=3 0.0168075208
u=4 0.2285822829
u=5 0.7543215336
> draw.unique(1:6,6,37)
Prob
u=1 1.442086727e-08
u=2 1.609368788e-05
u=3 0.001635326349
u=4 0.04015634701
u=5 0.3058060272
u=6 0.6523861913
> draw.unique(1:7,7,37)
Prob
u=1 3.897531695e-10
u=2 8.839601884e-07
u=3 0.0001478177871
u=4 0.005843959024
u=5 0.07714025911
u=6 0.3702732437
u=7 0.546593836
> draw.unique(1:8,8,37)
Prob
u=1 1.053386945e-11
u=2 4.816085111e-08
u=3 1.282140454e-05
u=4 0.000767611915
u=5 0.01563653901
u=6 0.1267602096
u=7 0.4136385786
u=8 0.4431841913
> draw.unique(1:9,9,37)
Prob
u=1 2.846991742e-13
u=2 2.613538419e-09
u=3 1.085130903e-06
u=4 9.476690309e-05
u=5 0.002797672655
u=6 0.03407920286
u=7 0.1844604472
u=8 0.4312062402
u=9 0.3473605824
> draw.unique(1:10,10,37)
Prob
u=1 7.694572276e-15
u=2 1.415493516e-10
u=3 9.045585277e-08
u=4 1.124221792e-05
u=5 0.0004625857048
u=6 0.007945966003
u=7 0.06345076808
u=8 0.2427963064
u=9 0.4224655732
u=10 0.2628674678
> draw.unique(1:11,11,37)
Prob
u=1 2.079614129e-16
u=2 7.658802913e-12
u=3 7.468156368e-09
u=4 1.298496505e-06
u=5 7.253842474e-05
u=6 0.001688609151
u=7 0.01866163034
u=8 0.1039430674
u=9 0.2930617039
u=10 0.3907489386
u=11 0.1918222062
> draw.unique(1:12,12,37)
Prob
u=1 5.620578726e-18
u=2 4.141916875e-13
u=3 6.127710055e-10
u=4 1.472406307e-07
u=5 1.096060833e-05
u=6 0.0003365644458
u=7 0.004945359353
u=8 0.03760522836
u=9 0.15275417
u=10 0.3273842458
u=11 0.3421693408
u=12 0.1347939827
> draw.unique(1:13,13,37)
Prob
u=1 1.519075331e-19
u=2 2.239420854e-14
u=3 5.007593853e-11
u=4 1.648099289e-08
u=5 1.612486013e-06
u=6 6.405746328e-05
u=7 0.001217594954
u=8 0.01214061101
u=9 0.06663078791
u=10 0.2040799789
u=11 0.3406280375
u=12 0.2841602879
u=13 0.09107701537
> draw.unique(1:14,14,37)
Prob
u=1 4.105609004e-21
u=2 1.210645561e-15
u=3 4.081394943e-12
u=4 1.827744688e-09
u=5 2.326027792e-07
u=6 1.178227925e-05
u=7 0.0002840255686
u=8 0.003612236128
u=9 0.02572310299
u=10 0.10558005
u=11 0.2501910227
u=12 0.3315203359
u=13 0.224000227
u=14 0.05907698294
> draw.unique(1:15,15,37)
Prob
u=1 1.109624055e-22
u=2 6.544429522e-17
u=3 3.320691196e-13
u=4 2.013444914e-10
u=5 3.306295867e-08
u=6 2.111809849e-06
u=7 6.36062064e-05
u=8 0.001011315029
u=9 0.009088183097
u=10 0.04800128064
u=11 0.1514260162
u=12 0.2833300168
u=13 0.3027030094
u=14 0.1676508975
u=15 0.03672352994
> draw.unique(1:16,16,37)
Prob
u=1 2.998983933e-24
u=2 3.537637435e-18
u=3 2.698642997e-14
u=4 2.207211664e-11
u=5 4.647544907e-09
u=6 3.710506425e-07
u=7 1.380296081e-05
u=8 0.0002702353088
u=9 0.003003291452
u=10 0.01985086306
u=11 0.08004650691
u=12 0.1982982871
u=13 0.297794312
u=14 0.2597833728
u=15 0.1191033403
u=16 0.02183561239
> draw.unique(1:17,17,37)
Prob
u=1 8.10536198e-26
u=2 1.912265631e-19
u=3 2.191435331e-15
u=4 2.410973113e-12
u=5 6.477325509e-10
u=6 6.418987275e-08
u=7 2.922251233e-06
u=8 6.962084581e-05
u=9 0.000942336406
u=10 0.007637859222
u=11 0.0382833751
u=12 0.1205618547
u=13 0.2386157631
u=14 0.2914602894
u=15 0.2097720994
u=16 0.08026062934
u=17 0.01239318541
> draw.unique(1:18,18,37)
Prob
u=1 2.190638373e-27
u=2 1.033664984e-20
u=3 1.778648357e-16
u=4 2.626594933e-13
u=5 8.968175317e-11
u=6 1.096936968e-08
u=7 6.066390456e-07
u=8 1.742254874e-05
u=9 0.0002837846536
u=10 0.002777405719
u=11 0.01695511689
u=12 0.06600297323
u=13 0.1652986835
u=14 0.2650600639
u=15 0.2662207607
u=16 0.1594366556
u=17 0.05124749644
u=18 0.006699019142
> draw.unique(1:19,19,37)
Prob
u=1 5.920644251e-29
u=2 5.587399606e-22
u=3 1.443125108e-17
u=4 2.855906426e-14
u=5 1.235341971e-11
u=6 1.856379302e-09
u=7 1.239601021e-07
u=8 4.258907062e-06
u=9 8.26842107e-05
u=10 0.0009654061483
u=11 0.007067465952
u=12 0.03332077616
u=13 0.1026745193
u=14 0.2075137648
u=15 0.2726944022
u=16 0.2272390061
u=17 0.1140372218
u=18 0.03096033171
u=19 0.003440036857
> draw.unique(1:20,20,37)
Prob
u=1 1.600174122e-30
u=2 3.020221764e-23
u=3 1.170629977e-18
u=4 3.100727556e-15
u=5 1.694852639e-12
u=6 3.117185201e-10
u=7 2.500725604e-08
u=8 1.021352961e-06
u=9 2.345043787e-05
u=10 0.0003234924157
u=11 0.002805624094
u=12 0.01577306564
u=13 0.05858886907
u=14 0.14511841
u=15 0.2395468277
u=16 0.2604081337
u=17 0.1813689702
u=18 0.07670352451
u=19 0.01766505413
u=20 0.001673531444
Side note , I heard a rumor that after much complaining about and boycotting of their high limit room wheel after it went to a 00 last year , they are putting the single zero back as of tomorrow. I look forward to losing only half as much now.
Quote: QFITOld story. BJ dealer once told me he dealt himself six BJs in a row with a high bettor at the table. The player picked up his chair and smashed against the table. Dealer said he didn't blame him.
I've had a dealer get 7 in a row. Yes it was a super high count and some aces up, so insurance was warranted and won.
Quote: chaosrevoltI have used lots of different systems and lost however the only reason they dont work is the table limit. if there was no table limit and a gambler had infinite amount f money they would all work.
Ever read John Scarne's Complete Guide to Gambling? Scarne tells a story of a Curacao casino that asked for his help when it was losing money on roulette. Scarne's solution: reduce the maximum/minimum table limits to prevent a Martingale-type system from winning too many times. Keeping too many people from short-term wins using systems like this is one of the reasons the limits exist. You are right that every system works with "infinite time and budget," but you have neither of those.
If "25 different numbers in a row" "never" happens, then here's a guaranteed can't-miss sure-fire system:
(a) Wait until 24 different numbers in a row show up
(b) Bet on all 24 of those numbers
(c) One of them will win (otherwise that's "25 different numbers in a row") - profit!
(d) What if one of the other 13-14 numbers shows up? Don't look at me; I'm not the one who claimed that 25 different numbers in a row "never" happens.
Remember, on a double-zero wheel, the probability of N different numbers coming up in consecutive spins is only (39-N) / (N-1) times the probability of the same N spins having (N - 1) different numbers coming up followed by one of those (N - 1) numbers coming up again. (It is (38-N) / (N-1) times as likely on a single-zero wheel.)
Quote: chaosrevolti would bet everything even my lungs and my kidneys u cant get 1 2 3 4 5 6 7 8 9 10 to come out which means a repeat must be more likely whatever anyone says.
Good thing you have two of each.
Looks like you've got it figured, but:
Your bet is not on the next number in a sequence, your bet is on the next spin.
And that's 1 in 38 every time, aina?
Quote: AxelWolfThere is a guy named TurboGenius on various roulette forums who preaches this exact type of system and claims to be making money.
I'll sell you a winning lottery system for $20. No refunds.
Perhaps you think I believe in such nonsense?Quote: gamerfreakI'll sell you a winning lottery system for $20. No refunds.
I was merely pointing out that there is someone else out there with the same ridiculous beliefs.
Quote: ThatDonGuyEver read John Scarne's Complete Guide to Gambling? Scarne tells a story of a Curacao casino that asked for his help when it was losing money on roulette. Scarne's solution: reduce the maximum/minimum table limits to prevent a Martingale-type system from winning too many times. Keeping too many people from short-term wins using systems like this is one of the reasons the limits exist. You are right that every system works with "infinite time and budget," but you have neither of those.
Scarne's book is interesting for history and rules. But, he really had little understanding of the math. His BJ chapter was modified after his death to remove some of the embarrassing stuff. There are many reasons that casinos assign different limit ranges to different tables:
· Chip trays have a fixed amount of space. It makes no sense to populate every tray with every size chip.
· High-limit players often do not like to play with low-limit players and low-limit players often do not like to play with high-limit players. So, they are segregated to a degree.
· The high-limit tables are watched more carefully.
· High-limit tables are less likely to be manned by less experienced dealers.
· Winning-hand payoffs are slower if players are betting many different chip sizes.
· High-limit tables are kept less crowded to provide more comfort to higher-limit players and to speed the play of larger bettors. Speed is just as important to the casino as it is to the advantage player. Some high-limit tables are often kept in separate areas or even on a separate floor.
· The limits also prevent ridiculously large bet changes, which could be of value to an advantage player.
Table limits are NOT there to prevent Martingale, which will lose even with no table limits.
While I'm wishing... What if casinos made dealers that expose hole cards wear a hat... That would be useful to.
My grandma used to tell me that I should wish in one hand and poop in the other and see which hand fills up first.
And all will ultimately fail.Quote: chaosrevoltHi, I have been working on a system that involves repeating numbers. To be honest i have tried every single system i could research or conjure up on my own and all have ultimately failed
Impossible to beat legally.Quote:but despite that and every mathematician telling me roulette is impossible to beat
that are totally unrelated to the fact that it already hit. Totally, completely unrelated to that fact. The wheel does not know that number already hit; the little white ball doesn't know it already hit and neither of them have a desire for the natural order of the universe to prevail.Quote:A number that has already hit has odds
No, 48.7 percent of the time you will see that.Quote:as 50% of the time you will see a repeat before the 8th spin.
Quote: FleaStiff
Impossible to beat legally.
More accurately, impossible to beat legally with a pure betting strategy.
That is the key. That casino which allowed a visiting Englilshman (Irishman?) to bet his entire life's savings on one spin of the roulette wheel actually called in their most experienced croupier despite the fact that it was his day off. The casino execs are no fools. They watch their employees closely.Quote: QFITHigh-limit tables are less likely to be manned by less experienced dealers.
I've not seen any of those posts but I would assume that somewhere someone is selling seminars on any system that is touted on those forums/fora/whatever.Quote: AxelWolfThere is a guy named TurboGenius on various roulette forums who preaches this exact type of system and claims to be making money.
Years ago there was a guy twittering about his table games winnings: visit different casinos and played different table games. Heavily into the plus column on twitter. Then someone followed him: he spent the day playing low stakes poker and then went home and twittered his craps, roulette and black jack winnings.
Quote: AxelWolfPerhaps you think I believe in such nonsense?
I was merely pointing out that there is someone else out there with the same ridiculous beliefs.
lol it was a joke, I guess too subtle