What is .99 repeating as a fraction?
Quote: thecesspitNo I don't. I have shown a proof that 0.9999... = 1. I cannot prove 0.999... != 1, because I don't make that hypothesis. It's assinine to state "X is true, now you go prove it, though you have stated X is false".
If I understand what you're saying, you think .999...! the product of .999... x.999... is different then .999... I assume it's because at the end of the number there's suppose to be an 8, right?
I have myself shown that at least 1 of your proofs was nonsense.
I think .999...! is nonsense too. Infinity still equals infinity, right? They didn't go and change that on me did they.
That should be 1 of your proofs for .999... is equal to 1 is nonsense.
Quote: DocI don't think anyone is using the ! symbol, which usually means "factorial". Some posters here use the two-character symbol != for "not equal". I assume that is because they are not confident that the usual symbol of ≠ will show up properly for everyone. (Did it look right to you when I just used it?)
It's actually because != is the symbol for "not equals" in the majority if modern programming languages. C++, Java, C#, PHP, Python, etc. And most people don't know how to type non-ASCII characters. I don't have the Unicode sequence for ≠ memorized: I used cut-and-paste just now.
Quote: MathExtremistIt's actually because != is the symbol for "not equals" in the majority if modern programming languages. C++, Java, C#, PHP, Python, etc. And most people don't know how to type non-ASCII characters. I don't have the Unicode sequence for ≠ memorized: I used cut-and-paste just now.
Good answer. I only began to learn about != from this thread, because "modern programming languages" are foreign languages to me. I did study Fortran II-D back about 1964 or 65, and I learned 1401SPS about the same time. Learned a little BASIC, too, but I have forgotten all of those. I suppose I am an antique.
Also, I don't remember any Unicode sequences. I use a Mac, and ≠ is just "Option key plus =", which isn't too difficult to remember.
No EVEN BOB, not the human variety.
Quote: thecesspitDoesn't need to.
The hypothesis is 1 = 0.999....
The proof is given, and the last line of the proof shows 1 = 0.999....
Your proof does not show 0.9999.... != 1.
Thus it is not a proof.
Okay, thanks for the explanation of what != meant. Needless to explain, I'm not familiar with the symbol. Probably, needless to point out, enjoying a few cocktails today.
That equation they use for the proof, is an equation that sets out to prove, if I'm not mistaken, that all numbers are equal to themselves (and not any other number). I think you're missing my point. The math you're doing to come up with 1, is fine. The equation does not work. At least not for all numbers. I think someones been BSing you.
I think your number machine is broken. Mine is still working fine, though. .999... = .999...
Quote: JyBrd0403Okay, thanks for the explanation of what != meant. Needless to explain, I'm not familiar with the symbol. Probably, needless to point out, enjoying a few cocktails today.
That equation they use for the proof, is an equation that sets out to prove, if I'm not mistaken, that all numbers are equal to themselves (and not any other number). I think you're missing my point. The math you're doing to come up with 1, is fine. The equation does not work. At least not for all numbers. I think someones been BSing you.
I think your number machine is broken. Mine is still working fine, though. .999... = .999...
Yes, someone is BS-ing me. You are COMPLETELY right about that.
Enjoy happy hour.
Quote: thecesspitYes, someone is BS-ing me. You are COMPLETELY right about that.
Enjoy happy hour.
.
Do you need me to explain the . symbol?
Quote: JyBrd0403.
This is the most sensible post of yours in this whole thread.
I guess, it's just a tough guy thing.
Yeah, I still say . I just want to make sure we're all on the same page.
Quote: JyBrd0403You wanted a mathematical proof .999... is not equal to 1, here it is.
x = .999...
10x = 9.999...
10x + x = 9.999... + .999...
11x = 10.999...
x = .999...
With this equation any number you put into the top of the equation, you will get the same number on the bottom. Put 8 into the top of the equation, and you will get 8 on the bottom. And, guess what:) put .999... into the top of the equation, and you get .999... at the bottom. That's proof .999... = .999... and not 1.
So, how's my equation doing? Anyone besides me been throwing numbers into the top of the machine and seeing what comes out on the bottom?
So far so good.
Consider that the series of 9s is getting infinitesimally smaller. Once you've hit 10^87 9s, equal to the largest estimate of number of particles in the universe, there is still an infinite number of 9s to go. There will NEVER be a limit where you can stop, or round off, or anything.
I mean, aside from the fact that it's just an artifact of using base 10 to notate numbers, and that numbers are ideas, not their representations in mathematical language.
Quote: MoscaJyBrd, on the off chance that you're not just drunk-trolling for S&G,
Consider that the series of 9s is getting infinitesimally smaller. Once you've hit 10^87 9s, equal to the largest estimate of number of particles in the universe, there is still an infinite number of 9s to go. There will NEVER be a limit where you can stop, or round off, or anything.
I mean, aside from the fact that it's just an artifact of using base 10 to notate numbers, and that numbers are ideas, not their representations in mathematical language.
I think a series of 9s would get infinitely greater, wouldn't it?
I mean, aside from the fact that it's just an artifact of using base 10 to notate numbers, and that numbers are ideas, not their representations in mathematical language.
Welcome to tough guy universe. Numbers are ideas, and not their representations in mathematical language.
I agree. Care to challenge me on the point? LOL.
How do you disprove an idea?
I guess some ideas you can disprove, huh?
I guess, I should have said challenge me on the point, Welcome to tough guy universe.
First part correct; second part incorrect.Quote: JyBrd0403That's proof .999... = .999... and not 1.
I think that everyone would agree that you and others can prove that .999... = .999... without much trouble. We are still waiting for some "proof" that .999... ≠ 1.
Troll on.
Quote: JyBrd0403I think a series of 9s would get infinitely greater, wouldn't it?
I mean, aside from the fact that it's just an artifact of using base 10 to notate numbers, and that numbers are ideas, not their representations in mathematical language.
Welcome to tough guy universe. Numbers are ideas, and not their representations in mathematical language.
I agree. Care to challenge me on the point? LOL.
How do you disprove an idea?
I guess some ideas you can disprove, huh?
Yeah, you're drunk trolling. Bye.
Quote: JyBrd0403Same proof, doc.
A proof of one equality does not prove a different inequality. Most people here (almost everyone except you, I think) would say that the proof of the equality .999... = .999... is both obvious and a bit in conflict with the claim that .999... ≠ 1.
Change the left hand side of each expression from .999... to X:
(a) X = .999...
(b) X ≠ 1
Most here would agree that if (a) is true then (b) is false. You can't prove both (a) and (b) to be true, but we're still waiting for you to offer a rational attempt at a proof.
Quote: MoscaYeah, you're drunk trolling. Bye.
See ya later.
Quote: DocA proof of one equality does not prove a different inequality. Most people here (almost everyone except you, I think) would say that the proof of the equality .999... = .999... is both obvious and a bit in conflict with the claim that .999... ≠ 1.
Change the left hand side of each expression from .999... to X:
(a) X = .999...
(b) X ≠ 1
Most here would agree that if (a) is true then (b) is false. You can't prove both (a) and (b) to be true, but we're still waiting for you to offer a rational attempt at a proof.
Huh?
My equation is an offer of proof that all numbers are equal to themselves. Like I said before, doc. So far so good.
Your proof had some problems with certain numbers.
Mine doesn't.
If my equation is correct. .999... will equal .999...
If my equation is incorrect .999... just might equal 1.
Quote: DocChange the left hand side of each expression from .999... to X:
(a) X = .999...
(b) X ≠ 1
Most here would agree that if (a) is true then (b) is false. You can't prove both (a) and (b) to be true, but we're still waiting for you to offer a ration attempt at a proof
LOL. I can't prove that a and b are both true. LOL.
I wasn't even trying to doc, you were. LOL.
Nevermind, I guess you proved MY point. LOL!
I must be drunk, I don't even know what your point is? ROTFL!
I'm sorry, I can't prove x = .999... and that x doesn't equal 1. ROTFL. I don't have to, doc. You do! ROTFL.
Ever have one of those laughing fits? I just did.
I'm sorry, doc, but, you are saying that x = .999... and not 1. right? ROTFLMAO.
Quote: JyBrd0403Disregard the last post. I see your point now. Tricky, but funny.
You really just don't understand a lot of things, do you?
I stick with my previous remark. If you believe that x.999... + .999... = x.999... + 1, then I think my work here is done.
I don't know what else to say.? LOL.
How's my equation doing, anyway..
I'm sorry, I can't help it, tonight. ROTFLMAO.
Quote: JyBrd0403I'm sorry, triplell. But a) is .999. = .999... , and b) .999... does not equal 1. Then, I have to prove that a) and b) are true? It's self evident isn't it. I'm dying here. ROTFL.
I don't know what else to say.? LOL.
How's my equation doing, anyway..
I'm sorry, I can't help it, tonight. ROTFLMAO.
You can prove .999... = .999... by simply stating : .999... = .999...
You won't be able to prove .999... does not equal (!=) 1.
"Then, I have to prove that a) and b) are true?"
There is no "Then,...", you've already prooved them (but you won't be able to prove b)
Once again, if you say .999... + 9.999... = 10.999..., then you are correct, and everyone will praise you for your excellent math skills...
.999... + 9.999... = 10.998....
*eyeroll* Will this thread ever die?
Quote: YoDiceRoll11No,
.999... + 9.999... = 10.998....
*eyeroll* Will this thread ever die?
Nopre .999... + 9.999... != 10.998.... as that implies 10.99888888.... which I am sure is not what you intend to mean.
10.99.....8 instead?
Quote: thecesspitNopre .999... + 9.999... != 10.998.... as that implies 10.99888888.... which I am sure is not what you intend to mean.
10.99.....8 instead?
I knew I didn't want to look at this thread today. Really wasted the other night.
Only problem with 10.999...8 is that the .999... runs off to infinity. You can't put an 8 at the end of the number, because the 9's never end. .999... is a series of never ending 9's, and 9.999.... is a series of never ending 9's. So, while I understand you're point. It just doesn't make sense to put an 8 after infinity.
Quote: JyBrd0403I knew I didn't want to look at this thread today. Really wasted the other night.
Only problem with 10.999...8 is that the .999... runs off to infinity. You can't put an 8 at the end of the number, because the 9's never end. .999... is a series of never ending 9's, and 9.999.... is a series of never ending 9's. So, while I understand you're point. It just doesn't make sense to put an 8 after infinity.
Holy shit, I think we might be getting somewhere....
So now, we have 9.999... + .999... = 10.999... (which you agreed on)
Take the same equation and change it to 9.999... + 1 = 10.999...
Whether you add .999... or 1, you get the same result, which means that there is no difference between the number, which in turn, means they are the same number.
Now I know that somewhere along that explanation, you are going to disagree.
Which I guess is fine. As long as when you add numbers together, you do it correctly, I don't care.
If you take 0.437 and add .999... to it, and you get 1.436999..., I'll be fine with that, because it's the same number as 1.437
Quote: TriplellHoly shit, I think we might be getting somewhere....
So now, we have 9.999... + .999... = 10.999... (which you agreed on)
Take the same equation and change it to 9.999... + 1 = 10.999...
Whether you add .999... or 1, you get the same result, which means that there is no difference between the number, which in turn, means they are the same number.
Now I know that somewhere along that explanation, you are going to disagree.
Which I guess is fine. As long as when you add numbers together, you do it correctly, I don't care.
If you take 0.437 and add .999... to it, and you get 1.436999..., I'll be fine with that, because it's the same number as 1.437
.999... is very close to being 1 anyway. But, I think it has some different properties then 1 does, namely all those 9's, and that decimal point, and that 0 where the 1 is in 1.
I think my equation is a pretty good proof that all numbers are equal to themselves, and .999... is equal to .999... I can't find any flaws with it. Anyone know a professor that can look it over?
Is (3/3) not 1? I mean there are threes in it, and a slash. It must be a different number...
And your proof that x = x isn't going to impress anyone...
Quote: TriplellIf you subtract two numbers, and the difference is zero, the numbers are the same. You get 10.999... Whether you add 1 or you add .999... How can both numbers produce the exact same result and be different?
Is (3/3) not 1? I mean there are threes in it, and a slash. It must be a different number...
And your proof that x = x isn't going to impress anyone...
Again, triplell, you proved my point. If you subtract 1 - .999... = a number > 0 not 0 itself. I know you will argue it is zero, but now you lack proof of that. Your equation doesn't support the fact that .999... = 1
Yes, when you do the equation and divide 3 by 3 it will then result in the number 1. The 3 on top is a 3, and the 3 on the bottom is a 3, you have to do the equation in order to get 1.
Your saying .999... is not equal to .999..., only 1? I think your arguement would be better stated that .999... is either .999... or 1 however you care to represent it. It's just that theory is incorrect.
Yes, 9.999... + 1 = 10.999... and 9.999... + .999... = 10.999...
They both produce the same result because of infinity. Infinity, itself has no numeric value. So, it's tough to put an 8 at the end of it.
Quote: JyBrd0403Again, triplell, you proved my point. If you subtract 1 - .999... = a number > 0 not 0 itself. I know you will argue it is zero, but now you lack proof of that. Your equation doesn't support the fact that .999... = 1
I didn't prove your point. You have two options, you can say 1 - .999... = 0, or 1 - .999... is undefined. You can't say it's a value > 0.
Your proof only supports that .999... = .999..., which I stated, no one will be impressed with. There is hundreds of proofs to which .999... = 1.
x = .999...
10x = 9.999...
10 - x = 9.999... - x
9x = 9
x = 1
Quote: JyBrd0403
Yes, when you do the equation and divide 3 by 3 it will then result in the number 1. The 3 on top is a 3, and the 3 on the bottom is a 3, you have to do the equation in order to get 1.
three-thirds is a fraction, it is equivilent to 1.
Quote: JyBrd0403
Your saying .999... is not equal to .999..., only 1? I think your arguement would be better stated that .999... is either .999... or 1 however you care to represent it. It's just that theory is incorrect.
I am saying that .999... is 1. So yes, it is equal to 1. It is also the same as .999... if you prefer that representation. The number is the same, much like three-thirds is also the same. There is no rule in math that says there exist only 1 representation of each number, you seem to be stuck on this.
Quote: JyBrd0403
Yes, 9.999... + 1 = 10.999... and 9.999... + .999... = 10.999...
They both produce the same result because of infinity. Infinity, itself has no numeric value. So, it's tough to put an 8 at the end of it.
The fact of the matter is you get the same result when adding both numbers. If 9.999.. + x = 10.999... and 9.999... + y = 10.999..., then x = y.
-Your proof only supports that .999... = .999..., which I stated, no one will be impressed with. There is hundreds of proofs to which .999... = 1.-
I just need 1 to disprove it, though.
x = .999...
10x = 9.999...
10 - x = 9.999... - x
9x = 9
x = 1
Perhaps, you missed my previous post on this. The equation you are using sets out to prove that all numbers are equal to themselves. The problem is your equation doesn't work. Go back and read my post on this if you missed it.
-There is no rule in math that says there exist only 1 representation of each number, you seem to be stuck on this.-
Oh thank goodness, I'll never be wrong on another math problem again, now that I can just say all numbers are equal to all other numbers. 2 + 2 = 5. You're 100% correct. LOL. Because, 5 is equal to 4 , too. LOL.
three-thirds is a fraction, it is equivilent to 1.
How do you prove this? Divide 3 by 3, I'll assume?
-The fact of the matter is you get the same result when adding both numbers. If 9.999.. + x = 10.999... and 9.999... + y = 10.999..., then x = y.-
And, now, you see why these numbers are so much fun. In this particular equation x= .999... or 1, and y = .999... or 1. LOL. My equation doesn't have that problem, though.
Again, this is an equation that sets out to prove all numbers are equal to themselves, and not any other number.
x=.999...
10x = 9.999...
10x + x = 9.999... + .999...
11x = 10.999...
x = .999...
x = 1
10x = 1
10x + x = 10 + 1
11x = 11
x = 1
Therefore, .999... and 1 are two different numbers.
Quote: BrooklynJakeHere is a demonstration that the repeating decimal expansion 0.9999... really equals 1. Choose a very small number, let's say 10 to the minus 50 (10 ^ -50). Let B = 1 - (10 ^ -50) = 0.999 ..9 (50 nines). Now just go out to 51 places, let A = 0.9999 ...9 (51 nines). So the number A is larger than B (because it has one more 9) and in turn, A is less than 0.999... (9 repeated infinitely) and that is less than or equal to 1. So, no matter how many decimal places you go out, 0.999... (9 repeated infinitely) will be even closer to 1. I won't show it here, but 0.999... (9 repeated infinitely) actually achieves it's limit of 1. This is roughly equivalent to a puzzle from ancient times. You travel at constant speed towards a city and you get half way there then you travel some more and you travel one quarter the distance, so you are 3/4 the way, then an 1/8 the way and that sums to 7/8 of the way there, then 1/16, 1/32 and so on. Will you ever get to the city? Answer: Yes, you will! You do it all the time.
If you only travel half the distance every day you will NEVER get there.
Quote: ALFERALFERIf you only travel half the distance every day you will NEVER get there.
Plus it will take twice as long to get back to the starting point.
Quote: ALFERALFERIf you only travel half the distance every day you will NEVER get there.
If you traveled for infinite days, you would get there.
It is equivilent to 0.111... in binary, which is 1 :)
relevant: Repeating Decimals
Yeah!Quote: Triplellrelevant: Repeating Decimals
That is why I started this thread.
What fraction is a certain repeating decimal.
The sum of a geometric series. Duh!
.999... = 9/10 + 9/10^2 + 9/10^3 + 9/10^4 + ...
=
a/1-r
(9/10 / 1-1/10)
Yahoo!
XOXOX
If you have a series of values and the first value is 0 and you are to average the remaining values, let's say the next series of values will be all 1's, to infinity, will the average of the values ever get to 1?
0+1+1+1+1+1+..../n = ???
Quote: YoDiceRoll11New question for everyone:
If you have a series of values and the first value is 0 and you are to average the remaining values, let's say the next series of values will be all 1's, to infinity, will the average of the values ever get to 1?
0+1+1+1+1+1+..../n = ???
That depends on what your definition of "dividing by infinity" is.
The solution = 1 - 1/n; for all finite n, this < 1, but your question specified infinity (which also means that you cannot specify any particular value < 1 as the result).
Quote: TriplellIf you traveled for infinite days, you would get there.
It is equivilent to 0.111... in binary, which is 1 :)
relevant: Repeating Decimals
If you travel for infinite days you'll never get there, you'd always be traveling, and never arriving. Must have run into a black hole on the way there. LOL.
In binary, I believe, .111... is equal to 1/1, not 1. 1/1 is equal to .999... or 1, though.
Quote: mustangsallyYeah!Quote: Triplellrelevant: Repeating Decimals
That is why I started this thread.
What fraction is a certain repeating decimal.
The sum of a geometric series. Duh!
.999... = 9/10 + 9/10^2 + 9/10^3 + 9/10^4 + ...
=
a/1-r
(9/10 / 1-1/10)
Yahoo!
XOXOX
I'm confused. What's 9/9 in binary? 9 or 8.999... , right? I might have been wrong, sally? I don't know if 9/9 would equal .999... Except for that proof on wikipedia where .333... x .333... = .999... Don't know if that would hold up though. That whole dividing 9 by 9 thing gets me now. :)
9/9 is 1, which is 1 in binary. 1001b/1001b
Binary is just another way to represent numbers. You don't seem to understand that numbers are ambiguous. I concluded this when you mocked me for stating that values can have more then one representation.
JyBrd, answer this question.
How would you go about producing 0.999... repeating. Repeating decimals are created from flaws in the decimal number system. All fractions have a corresponding repeating decimal.
So for instance, we have (1/3), which in decimal is represented as 0.333... If you want to get to 0.999..., you multiply it by 3. Since 0.333... also represents (1/3), this clearly shows that the value is 1.
(1/9) = 0.111... Again, to get to 0.999..., you multiply by 9, which again, is clearly 1.
How else would you produce 0.999... ?
Quote: TriplellI don't think you understand binary...
9/9 is 1, which is 1 in binary. 1001b/1001b
Binary is just another way to represent numbers. You don't seem to understand that numbers are ambiguous. I concluded this when you mocked me for stating that values can have more then one representation.
JyBrd, answer this question.
How would you go about producing 0.999... repeating. Repeating decimals are created from flaws in the decimal number system. All fractions have a corresponding repeating decimal.
So for instance, we have (1/3), which in decimal is represented as 0.333... If you want to get to 0.999..., you multiply it by 3. Since 0.333... also represents (1/3), this clearly shows that the value is 1.
(1/9) = 0.111... Again, to get to 0.999..., you multiply by 9, which again, is clearly 1.
How else would you produce 0.999... ?
You're right, I don't understand binary. I just looked it up on Google. Here's the URL http://en.wikipedia.org/wiki/Binary_numeral_system
But on this site, it shows 1/1 as equaling 1 or .999... which is what I'm saying. The fraction can be 1 or .999... either way you care to interpret that fraction. Just like when you said 9.999... + x = 10.999... x here could either be .999... or 1, if you were solving for x.
I don't think it is so much a flaw in the decimal system myself. I personally think .333... is just a more accurate expression of 1/3. I said in another post that when you chop a whole piece of pie into 3 pieces and then put it back together, something will get lost, a molecule or proton or neutron or something. While I think 1/3 is a valid. I think .333... is more accurate.
P.S. Didn't mean to mock you. Just trying to make a point. I don't believe numbers are ambiguous. There's a base number system. Fractions, decimals, binary, and all others are just offshoots. You said that repeating decimals are flaws in the decimal system, taking your point, saying 1/3 is .333... is a little misleading. It's better to just say it is the decimal representation of 1/3. IMO.
Quote: JyBrd0403I'm confused. What's 9/9 in binary? 9 or 8.999... , right? I might have been wrong, sally? I don't know if 9/9 would equal .999... Except for that proof on wikipedia where .333... x .333... = .999... Don't know if that would hold up though. That whole dividing 9 by 9 thing gets me now. :)
Nevermind, the 9/9 thing. For some reason I was thinking 9/1.
So, in binary, 9/9 would be .999... or 1, right? Just like 1/1 would be .999... or 1. I think that's right, binary is confusing me here.
Damn wikipedia didn't show 9/9. LOL.
Quote: JyBrd0403You're right, I don't understand binary. I just looked it up on Google. Here's the URL http://en.wikipedia.org/wiki/Binary_numeral_system
But on this site, it shows 1/1 as equaling 1 or .999... which is what I'm saying. The fraction can be 1 or .999... either way you care to interpret that fraction. Just like when you said 9.999... + x = 10.999... x here could either be .999... or 1, if you were solving for x.
I don't think it is so much a flaw in the decimal system myself. I personally think .333... is just a more accurate expression of 1/3. I said in another post that when you chop a whole piece of pie into 3 pieces and then put it back together, something will get lost, a molecule or proton or neutron or something. While I think 1/3 is a valid. I think .333... is more accurate.
P.S. Didn't mean to mock you. Just trying to make a point. I don't believe numbers are ambiguous. There's a base number system. Fractions, decimals, binary, and all others are just offshoots. You said that repeating decimals are flaws in the decimal system, taking your point, saying 1/3 is .333... is a little misleading. It's better to just say it is the decimal representation of 1/3. IMO.
I have a bachelors in computer engineering. I'm pretty well familiar with the binary number system.
I don't think you understand really anything about numbers and bases (and general math..which is not an insult, there is many things in this world I don't understand...and usually I'll take anyone's word about those things as fact)...
Anyway, you are mixing all sorts of apples, oranges, banana's..etc into this. First off, number systems are all about the "base". Think of it as units. Decimal (Base-10) is the most common, and each value is represented by 10 individual characters (0-9). Binary is base 2, and is represented by two characters (0-1). There is all sorts of bases, and some aren't even whole number values (base-pi, or base-e)...
Most people understand base-10, so let's just stick with that for this discussion.
Your pie metaphor is pretty irrelevant. Your theory should start with the math, and then applied in the application. The application shouldn't change the math. There is often minor discrepancies between the calculated math and the actual application. This doesn't say the math is wrong, it just means there is something not accounted for, but it's really not worth fussing over.
"It's better to just say it is the decimal representation of 1/3. IMO."
That's really the entire point. Every symbol is a xx representation of yy... The symbol '3', can be represented in so many different ways to mean the same thing.
This entire thread kind of scoped creeped into the different categories of math. The fact of the matter is, you could never represent the decimal representation of 0.999... as a fraction that doesn't equal 1, therefore, it must be equivalent to 1.
If you want to represent a number that is greater then 0.99 and < 1, you can do it with 0.991 to 0.999...9, with any finite number of 9's. if the number of 9's is not finite, then the value is 1.
I don't know why I continued to reply to your nonsense...but I did. You don't understand basic math principals, but you argue with math majors, and math professors, and really the entire scientific community, pointing the finger, stating they are wrong, and you are right.
But you're human, and that's what humans do. How many times have you heard "That doctor was an idiot...he had no idea what he was talking about"...from someone with no medical background.
So as I said before, you can continue to think that 0.999... isn't 1. You're wrong, but it's fine, as long as you aren't teaching my kids math...I don't really care...
Quote: TriplellSo as I said before, you can continue to think that 0.999... isn't 1. You're wrong, but it's fine, as long as you aren't teaching my kids math...I don't really care...
Guess that all depends on how my equation holds up to scrutiny. So, far, so good. See, since the equation is an offer of proof, you can't go around changing one number into a completely different number as you see fit, to make the equation fail or work to your liking, which is what you've been doing this whole time. See, I can't just take your equation and say well since x = .999... and .999... is 1, then x = 1, so you never proved that .999... is equal to 1 with your equation. That's stupid, and just simply NOT ALLOWED.
So, 9.999... + .999... = 10.999... and you can't change the damn .999... into 1, because this equation is an offer of proof, and not some BS debate, where you can just change one number into another at will.
The equation I'm offering, ends the stupid debate.
P.S I didn't appreciate being taught by you and your teachers, myself. BS artist if you ask me.
First off, you obviously don't understand what a proof is. But since you like wikipedia so much, here you go:
http://en.wikipedia.org/wiki/Mathematical_proof
Your proof, simply states that 0.999... is the same as 0.999... and as I said before, I'm not impressed.
Yes I did prove that 0.999... is 1 with my proof.
I took a value x, defined it as 0.999...
I then multiplied that value by 10, to get 10x = 9.999...
I then subtracted x from both sides.
10x - x = 9.999... - 0.999...
this equates to 9x = 9
I then divided by 9 on both sides
this equates to x = 1.
Valid math operations were performed throughout this entire proof.
Like I said before...You don't understand most concepts of math, and your ignorance is pretty apparent with all the bs that you post. I'm going to go ahead and stick with 99.999...% of those who are competent in math, and agree that 0.999... is 1
Quote: TriplellYou're self taught...that explains it.
First off, you obviously don't understand what a proof is. But since you like wikipedia so much, here you go:
http://en.wikipedia.org/wiki/Mathematical_proof
Your proof, simply states that 0.999... is the same as 0.999... and as I said before, I'm not impressed.
Yes I did prove that 0.999... is 1 with my proof.
I took a value x, defined it as 0.999...
I then multiplied that value by 10, to get 10x = 9.999...
I then subtracted x from both sides.
10x - x = 9.999... - 0.999...
this equates to 9x = 9
I then divided by 9 on both sides
this equates to x = 1.
Valid math operations were performed throughout this entire proof.
Like I said before...You don't understand most concepts of math, and your ignorance is pretty apparent with all the bs that you post. I'm going to go ahead and stick with 99.999...% of those who are competent in math, and agree that 0.999... is 1
I don't think you understand your equation, do you?
Again, this equation sets out to prove that all numbers are equal to themselves, and not any other number. Let me help you out here. That x= .999... on the top of the equation, it should say let x = .999... Now if x = .999... at the beginning of the equation then x has to equal .999... the equation can't change the fact, it can only prove it. x is not unkown here it's already been solved for, we already know the answer is .999... and not 1. The proof fails for .999... The tricky part is this equation works for most numbers. Some teacher of mine gave me this BS equation a long time ago. For some reason, I still recall it.
My equation, also proves that 1=1, 2=2, 3=3, 2.999... = 2.999... As a matter of fact, my equation proves that all numbers (what was the fancy term you used 10 base numbers or something) are equal to themselves. I think that's how you can get all those offshoots from that (what is it base 10 system). You have noticed that all those offshoots, Fractions, Decimals, binary, all use numbers from the base 10 system, haven't you?
