Pr0trek
Pr0trek
  • Threads: 1
  • Posts: 1
Joined: Nov 26, 2019
November 26th, 2019 at 3:07:44 PM permalink
Hi guys,

was looking for answer on this forum, checked first 20 pages but couldnt find an answer ;-) for some of you its probably easy to calculate this but for me...black magic, so how to calculate probability of lets say 15 numbers which did not appear yet to hit on the eight spin, or for example 10 numbers which did not appear yet to hit on the 15th spin, im talkin about roullete with one zero.

Thanks in advance.
MaxPen
MaxPen
  • Threads: 13
  • Posts: 3634
Joined: Feb 4, 2015
Thanked by
RSMission146
November 26th, 2019 at 3:48:06 PM permalink
Each number will have a 1/37 chance of hitting on any particular spin.

Disclaimer:
Some people seem to think a spin history board containing hamburger and french fry symbols may indicate otherwise.
Minty
Minty
  • Threads: 7
  • Posts: 536
Joined: Jan 23, 2015
November 26th, 2019 at 11:52:59 PM permalink
Quote: MaxPen

Each number will have a 1/37 chance of hitting on any particular spin.

Disclaimer:
Some people seem to think a spin history board containing hamburger and french fry symbols may indicate otherwise.



Now if there was a game to spin for actual hamburgers and french fries that would be something I'd be interested in.
"Just because I'm not doing anything illegal, doesn't mean I won't have to defend myself someday." -Chip Reese
RS
RS
  • Threads: 62
  • Posts: 8626
Joined: Feb 11, 2014
November 27th, 2019 at 1:03:41 AM permalink
Quote: Pr0trek

Hi guys,

was looking for answer on this forum, checked first 20 pages but couldnt find an answer ;-) for some of you its probably easy to calculate this but for me...black magic, so how to calculate probability of lets say 15 numbers which did not appear yet to hit on the eight spin, or for example 10 numbers which did not appear yet to hit on the 15th spin, im talkin about roullete with one zero.

Thanks in advance.


I don't think I quite understand your question. Are you saying what is the probability that a set of 15 numbers (say 1-15) do not hit within 8 spins?

If that's the question, then you're going to want to find the probability of losing on any given spin, which is 22/37 because there are 22 ways to lose. To figure out the probability to lose 8 spins in a row, you would just multiply 22/37 by itself 8 times. That's the same thing as raising it to the 8'th power.

(22/37)^8 = 0.01562311588 = 1.56% = 1-in-64.0077182847


EDIT: What possible system you might be cooking up, assuming that's what you're doing, I'll save you a bunch of time and money -- it's not going to work.
  • Jump to: