For example:
Trials=179
Successes= 5 or more hits
P=1/37(strait up bet)
How do you make the formula and what do of the terms mean?
Thanks in advance
In my example, how do you get the outcome?
And, what formulas to use.
Quote: ybotNice answers but, anyone knows the probability to hit 5 or more times after playing 179 spins on a singlezero wheel?
And, what formulas to use.
Use Excel : =1-POISSON.DIST(4,179/37,TRUE)
The formula calclulates getting 0-4 hits of an event with a mean value of 179 / 37. 179 is the number of spins. 1/37 the odds of it occuring each spin : 4.83 hits on average.
Result = 53%.
Quote: thecesspitUse Excel : =1-POISSON.DIST(4,179/37,TRUE)
The formula calclulates getting 0-4 hits of an event with a mean value of 179 / 37. 179 is the number of spins. 1/37 the odds of it occuring each spin : 4.83 hits on average.
Result = 53%.
Thank you very much for you help Thecesspit.
probability 7/37
sample=10
thanks in advance
Quote: ybotHi, I'd like to undestand this distribution used to work with roulette probabilities.
For example:
Trials=179
Successes= 5 or more hits
P=1/37(strait up bet)
How do you make the formula and what do of the terms mean?
Thanks in advance
First, I would not use the Poisson distribution, because it is meant for a large number of samples. Instead, I would use the binomial distribution.
In Excel: =BINOMDIST(4,179,1/37,TRUE)
You'll get a slightly different probability than using the poisson distribution. They're pretty close, but the binomial is the correct one.
Quote: ybotSupose we want to know the probabiity to lose 10 strait bets playing 7 numbers using poisoon distribution.
probability 7/37
sample=10
The probability is (30/37)^10 = 12.28%, but this also assumes that you don't care if you win or lose on the 11th bet.
Quote: CrystalMathThe probability is (30/37)^10 = 12.28%, but this also assumes that you don't care if you win or lose on the 11th bet.
What about 10 or MORE misses?
Quote: beachbumbabsI, too, thought this was about fishin' holes. Although, in a way, it still is. lol...D'oh!
:)
The probability of 10 or more is the same as I listed for 10, because this only takes into account the first 10 games and the 11th could be a loss or a win.
But, if you play exactly 179 games, the probabilitiy that you will have 1 or more streak of 10+ losses is 99.648%.