June 28th, 2012 at 12:47:49 PM
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I need some advice. Let's say I am playing backgammon and I am about to roll both dice. What are the odds that one of the die will be a 4 (no combinations like 3+1 or 2+2...)?
I assume it's 1/6 + 1/6 = 1/3.
My rationale is that if you place a bet that one out of two coins will be heads, the odds are 1.0 (1/2 +1/2)
I assume it's 1/6 + 1/6 = 1/3.
My rationale is that if you place a bet that one out of two coins will be heads, the odds are 1.0 (1/2 +1/2)
June 28th, 2012 at 12:54:04 PM
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Not exactly.
Think about the 36 combinations of dice throws.
5 had a 4 on one die and not the other, 5 have a 4 on the other and not the first. One combination has a 4 on both.
Therefore, its 11/36.
Similarly, the odds of getting heads when flipping two coins is either 75% for at least one head, or 50% for exactly one head.
Think about the 36 combinations of dice throws.
5 had a 4 on one die and not the other, 5 have a 4 on the other and not the first. One combination has a 4 on both.
Therefore, its 11/36.
Similarly, the odds of getting heads when flipping two coins is either 75% for at least one head, or 50% for exactly one head.
I invented a few casino games. Info:
http://www.DaveMillerGaming.com/ —————————————————————————————————————
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