Meaculpa
Meaculpa
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December 20th, 2012 at 6:16:56 PM permalink
I thought I read somewhere that the odds were about 1.7 million to one. Is this true? If it is, on the poker site I play on, I play tournaments and I get the same cards back to back in almost every tournament. Does that mean that they have a problem with their dealing software?
Ibeatyouraces
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December 20th, 2012 at 6:29:38 PM permalink
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tringlomane
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December 20th, 2012 at 7:47:13 PM permalink
Yeah, its 1 in 1326 for any hand being back to back since the first hand can be ANYTHING. If you don't require the exact same suits, the chances of two cards of the same rank as last hand is even higher.
DJTeddyBear
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December 20th, 2012 at 7:57:50 PM permalink
Quote: Ibeatyouraces

1 in 1326 to get the same random hand back to back and 1 in 1,758,276 to get a spicific hand like both red aces back to back.

In other words, 1 in 1,326 to get any specific hand on any specific deal. Therefore 1 in 1,326^2 of getting a specific hand twice in a row.

However, what often happens (and is often the reason for asking in the first place) is that you get dealt two cards and say, "Hey! I just had these cards." In that case, it's just the 1 in 1,326 odds, since you weren't really concerned about what the first hand was.

Mind you, you need to divide that by the number of hands you see (minus one), to get the odds that you'll have this experience during your poker game.
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sodawater
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December 20th, 2012 at 8:51:02 PM permalink
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Ibeatyouraces
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December 20th, 2012 at 9:42:50 PM permalink
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Ayecarumba
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December 21st, 2012 at 9:02:04 AM permalink
Quote: Ibeatyouraces

1 in 1326 to get the same random hand back to back and 1 in 1,758,276 to get a spicific hand like both red aces back to back.



Too be clear, on this Friday before a holiday week...

What are the odds of getting both red aces one time?

I get dealt the AdAh. I wasn't counting on getting this specific hand. Are my odds of getting these same two cards on the next hand, 1-in-1326, or 1-in 1.7 million?

Does the 1-in-1.7 million figure take into account the order you receive the cards? It just seems really high to me.
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Ibeatyouraces
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December 21st, 2012 at 9:09:26 AM permalink
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jml24
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December 21st, 2012 at 9:13:31 AM permalink
Quote: Ayecarumba

Too be clear, on this Friday before a holiday week...

What are the odds of getting both red aces one time?

I get dealt the AdAh. I wasn't counting on getting this specific hand. Are my odds of getting these same two cards on the next hand, 1-in-1326, or 1-in 1.7 million?

Does the 1-in-1.7 million figure take into account the order you receive the cards? It just seems really high to me.



As others have stated the odds of getting any specific hand are 1 in 1326. This figure ignores ordering because it doesn't matter for a poker hand. So that is the answer to your first two questions. Whenever you are looking at a hand, the odds of seeing that exact hand again on the next deal is 1 in 1326.

The 1,758,276 figure comes in if you were thinking of a specific hand in advance. Let's say you told a friend you had a feeling you would get black aces the next two hands in a row. Your next hand would be black aces one time in 1326 hands. For it to happen twice in a row would be one in 1326 * 1326 = 1,758,276.
Ayecarumba
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December 21st, 2012 at 11:29:19 AM permalink
Thanks folks for the clarification.

I think this could be the basis of a side bet in for UTH, or other Hold'em variants. "Call Your Rush" You get 1000 to 1 for predicting the rank and suits of your paired hole cards on the next hand, or you can get 1,000,000 to 1 for predicting your paired hole cards, and that they will repeat back to back. You can get smaller amounts for predicting that your cards will be suited, and naming the suit; getting the rank of the pair correct, but the suits wrong; or even whether the two cards will both be red or black. etc.
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boymimbo
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December 21st, 2012 at 11:51:29 AM permalink
The odds of getting one red ace followed by the other is 2/52*1/51 or 1,326:1 which is the same odds of getting any two named cards in a hand. The odds of you correctly guessing both of your cards in two hands in a row is (1,326:1)^2 or 1,758,276:1
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Buzzard
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December 21st, 2012 at 1:46:02 PM permalink
" "Call Your Rush" You get 1000 to 1 for predicting the rank and suits of your paired hole cards on the next hand, or you can get 1,000,000 to 1 for predicting your paired hole cards "

Gee, no incentive for dealer collusion there.
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tringlomane
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December 21st, 2012 at 7:49:26 PM permalink
Quote: Buzzard

" "Call Your Rush" You get 1000 to 1 for predicting the rank and suits of your paired hole cards on the next hand, or you can get 1,000,000 to 1 for predicting your paired hole cards "

Gee, no incentive for dealer collusion there.



Also if you don't verbally call it, you would need 52 spots on the table and two lammers to track your predicted hand. Would never work practically on a live table.
Buzzard
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December 21st, 2012 at 9:54:48 PM permalink
Well, it would work online. And I am sure you would get paid too. NOT !
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
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