Probability problem
November 23rd, 2012 at 8:45:49 PM
permalink
39 total cards are dealt to 3 players, 13 cards each to Player A, Player B and Player C. Two of the cards are jokers. What is the probability that at least one of the jokers winds up in Player B's hand? Thanks.
November 23rd, 2012 at 10:21:48 PM
permalink
Someone else will surely give you the exact answer.
Until then, the approximate answer is a probability of .5614.
Until then, the approximate answer is a probability of .5614.
November 23rd, 2012 at 10:43:12 PM
permalink
I can give you the exact answer: 416/741, approximately equal to 0.56140350877.
The math's pretty simple: the other two hands might as well be left in the deck, so just figure the chance of getting no jokers as (37 chs 13)/(39 chs 13), and take the complement.
The math's pretty simple: the other two hands might as well be left in the deck, so just figure the chance of getting no jokers as (37 chs 13)/(39 chs 13), and take the complement.
The trick to poker is learning not to beat yourself up for your mistakes too much, and certainly not too little, but just the right amount.
