thetruth90210
thetruth90210
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March 16th, 2013 at 2:38:14 AM permalink
I know nobody is going to believe this but I don't care- I would like to know the odds of this happening.

Here is what happened.
-Me and 3 buddies were playing poker tonight. The flop was 7, 8, 9, all of clubs. Turn was 4 of clubs. River was 3 of clubs.
This seems pretty unlikely the way it was but here was our hands.

-Ace-Queen, both clubs
-5-6, both clubs
-Jack-10, both clubs
-King-2, both clubs

-That means that all 13 clubs were in play + two players flopped straight flushes and one person had and king high flush and the other had and Ace high Flush.
-I know how ridiculous this seems, but I am 99.9% sure it wasn't set up, because we shuffle and cut the deck before every hand.

-So I was wondering if anybody knew the odds of this happening, or if they could point me in the right direction of where I could find out the odds of this happening.
-I was also wondering if anybody has had this, or something like this happen before?
Thanks
JB
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JB
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March 16th, 2013 at 4:26:19 AM permalink
The odds of it happening in any suit are 1 in 158,753,389,900 (assuming 4 players).
The odds of it happening in a specific suit (such as clubs) are 1 in 635,013,559,600.
Mosca
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March 16th, 2013 at 4:53:03 AM permalink
A long, long time ago I was playing contract bridge, and one of the players at the table was dealt 12 spades. That's the closest I've ever seen to something like that.
A falling knife has no handle.
Ibeatyouraces
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March 16th, 2013 at 7:47:51 AM permalink
deleted
DUHHIIIIIIIII HEARD THAT!
FinsRule
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March 16th, 2013 at 8:26:15 AM permalink
How'd the action go? How much money lost? Only 4 people playing total?

Edit - Saw only 4 people playing total.

I guess you have no reason to lie, but that's just crazy.
DJTeddyBear
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March 16th, 2013 at 5:03:58 PM permalink
Quote: JB

The odds of it happening in any suit are 1 in 158,753,389,900 (assuming 4 players).
The odds of it happening in a specific suit (such as clubs) are 1 in 635,013,559,600.


I'm unsure if that's the odds of "all 13 clubs" or the specific distribution you describe.

At any rate, that's for a specif hand. Divide by the total number of hands you've played lifetime to get the odds of you ever seeing that.

Of course, the short formula is rather simple: Shit happens.
I invented a few casino games. Info: http://www.DaveMillerGaming.com/ ————————————————————————————————————— Superstitions are silly, childish, irrational rituals, born out of fear of the unknown. But how much does it cost to knock on wood? 😁
onenickelmiracle
onenickelmiracle
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March 16th, 2013 at 5:19:10 PM permalink
The odds of it happening intentionally are much better than unintentionally.
I am a robot.
tringlomane
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March 16th, 2013 at 5:34:55 PM permalink
Quote: DJTeddyBear

I'm unsure if that's the odds of "all 13 clubs" or the specific distribution you describe.



It's just the odds of pulling all 13 clubs in 13 cards 1/(52!/39!/13!) and multiply that by 4 to get the chances of any suit. He will ask this question regardless of who has what ranks.
MangoJ
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March 16th, 2013 at 6:06:41 PM permalink
Quote: onenickelmiracle

The odds of it happening intentionally are much better than unintentionally.



The game was not just all spades, it was the two-highest post-flop flushes (A and K) against the two highest hands (lower and higher straight flush).
I bet the winning hand was among the player who either shuffled or had cut the deck.

If you ever want to bring in a cold deck, make it less "dramatic" (read as less obvious). Make it a set against one (or two) post-flop flushs, which turns into a full house at the river. Happens every day somewhere - and remember to let the button fold.
sodawater
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March 16th, 2013 at 6:26:40 PM permalink
if this really happened, it's 100 percent chance this was a cold deck, and cheating. It's not just the odds of 13 clubs being the first 13 cards off -- but also that two were perfect straightflushes, and the ace and king high flushes were all in separate hands. cannot happen.

someone is an amateur cheater and went way overboard with a ridiculous cold deck setup.
tringlomane
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March 16th, 2013 at 7:31:04 PM permalink
Quote: sodawater

if this really happened, it's 100 percent chance this was a cold deck, and cheating. It's not just the odds of 13 clubs being the first 13 cards off -- but also that two were perfect straightflushes, and the ace and king high flushes were all in separate hands. cannot happen.

someone is an amateur cheater and went way overboard with a ridiculous cold deck setup.



This is the most likely scenario for sure. But it "can" happen with a random deck. I totally missed the flopped straight flush in the post.
rudeboyoi
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March 16th, 2013 at 9:14:22 PM permalink
i remember being 19 and playing poker in my barn. there were four of us playing with a 5th person shuffling. we were playing 7card stud. i get rolled up kings. another player gets rolled up aces. another player gets rolled up queens. i ended up winning with kings full. aces didnt fill up. we thought it was just crazy luck but looking back on it, it was probably setup. and i guess i was being setup to lose the hand but lucked out cause aces didnt fill up and i did.
MrV
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March 16th, 2013 at 9:34:31 PM permalink
Never happened.

B.S.
"What, me worry?"
thetruth90210
thetruth90210
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March 16th, 2013 at 10:25:44 PM permalink
Thanks for your help, that isn't very good odds.
thetruth90210
thetruth90210
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March 16th, 2013 at 10:30:45 PM permalink
well pretty much we all just bet really small before the flop and after the flop. We all wanted to just slow play it.

2 of the guys, the one with king-two, and the one with 5-6 had very small stacks and went all in on the turn.

On the river the guy with Jack-Ten led out, the guy the ace raised, and then the Jack-Ten guy raised all in.

The guy with the ace had to call.

Then we just sat around for about and hour thinking about what happened. We were just stunned.
JB
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JB
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March 17th, 2013 at 2:36:08 AM permalink
Quote: DJTeddyBear

I'm unsure if that's the odds of "all 13 clubs" or the specific distribution you describe.


If the suit is unspecified I calculate it as follows:
combin(4,1) for the suit, multiplied by
combin(13,13) for selecting all 13 cards of that suit, divided by
combin(52,13) for the number of ways to select 13 cards from 52

If the suit is specific, omit the combin(4,1) term from the equation.
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