Double up blackjack

How often will the dealer have a total of 16?

Quote: Hunterhill

How often will the dealer have a total of 16?

Hunterhill,

Seems like she does every time I bust :-(

If you mean a 2-card 16, then we can calculate the answer. The dealer can have X6, 97, or 88. For a 6D shoe, these probabilities are as follows:

(2*96*24+2*24*24+24*23)/(312*311) = 0.06505070492

Thus, the dealer gets a 2-card 16 about 6.5% of the rounds.

The terms in the numerator represent the number of combinations of X6, 97, and 88, respectively. The 2's in the first two terms are present because the dealer can draw X6 or 6X (either order) and 97 or 79 (either order), the 96 is the total number of X's in the 6D shoe, the 24's are the total number of 6's, 7's, 8's, and 9's in the 6D shoe, and the 23 is the number of 8's left after the dealer gets the first 8. The denominator is the number of 2-card combinations in a 6D shoe.

Hope this helps!

Dog Hand

Thanks Doghand,actually its 16 with any number of cards.
After searching more I found the Wizard analysed this.

Quote: Hunterhill

Thanks Doghand,actually its 16 with any number of cards.
After searching more I found the Wizard analysed this.

And the Answer is . . . . ???

Or, at least provide the link, please.

gordonm888,

Hunterhill, the op, is referring to the BJ variant Double Up Blackjack: see

https://wizardofodds.com/games/double-up-blackjack/

In particular, the Bonus 16 sidebet available with Double Up Blackjack. This sidebet has already been analyzed here at WoV: see this thread:

https://wizardofvegas.com/forum/questions-and-answers/math/29660-new-side-bet-need-odds-math-please/1/

In the end, assuming H17 (but Stand on 16, since the dealer stands on ALL 16's), the dealer gets a 16 on 14.03% of the rounds.

Hope this helps!

Dog Hand