?? Avg # cards/hand
Fairly sure someone here knows the answer off top of head.
What is the total number of cards dealt, on average, in a single hand, counting both your's and dealers?
Again, heads up against the house.
If it varies much by game rules assume a fairly common:
3:2, H17, split to four, DAS, RSA-no, NS.
(Edit) guess I should add "with perfect basic strategy for game"
Or point me in the right direction to find answer.
Thanks
2.8, more or less.
Quote: Dieterhttps://www.blackjackincolor.com/cardsperround.htm
2.8, more or less.
Thx for the link, but the answer has be over 4, counting your's and dealers ;-)
(Edit) I'll run with 5.5, close enough after looking at chart(s)
Thanks again!
Quote: TwoFeathersATLThx for the link, but the answer has be over 4, counting your's and dealers ;-)
(Edit) I'll run with 5.5, close enough after looking at chart(s)
Thanks again!
I believe that's 2.8 cards per player?
Quote: TwoFeathersATLThx for the link, but the answer has be over 4, counting your's and dealers ;-)
(Edit) I'll run with 5.5, close enough after looking at chart(s)
Thanks again!
2.8 cards per spot in play.
There are always at least two spots - 1 player, 1 dealer, minimum... up to however many other players there are, plus a dealer.
Quote: Dieter2.8 cards per spot in play.
There are always at least two spots - 1 player, 1 dealer, minimum... up to however many other players there are, plus a dealer.
I knew what you meant, just wasn't exactly what I asked (silly questions usually ;-)
Thanks a third time, big kiss, and all that!
Edit - again. Of course my next problem was how the numbers change as you add additional players. But your link answered that as well. Nice.
The exception is when playing heads up, I believe the dealers average cards per round drops to closer to 2.7 because he/she does not complete hands when player has BJ or busts. For heads up action I use 5.5 for the both of us combined, so your 5.5 is spot on 2f.
Quote: kewljYep 2.8 cards per spot, including dealer is what I use. I use this to figure to estimate number of rounds played, dividing total cards by 2.8 x #spots.
The exception is when playing heads up, I believe the dealers average cards per round drops to closer to 2.7 because he/she does not complete hands when player has BJ or busts. For heads up action I use 5.5 for the both of us combined, so your 5.5 is spot on 2f.
I was just looking for a good approximation when I decided to go with 5.5.
Now I have your approval? I'm humbled..
Quote: TwoFeathersATLI was just looking for a good approximation when I decided to go with 5.5.
Just out of curiosity, 2f, what is your interest in that number about? I don't see much value in knowing it except for determining number of rounds you can expect, or estimating number of rounds you have already played.
Quote: kewljJust out of curiosity, 2f, what is your interest in that number about? I don't see much value in knowing it except for determining number of rounds you can expect, or estimating number of rounds you have already played.
You have already pegged the reason for my curiosity.
I'm just tilting at windmills, and searching for the Holy Grail,
And having some fun along the way ;-)
Largest player hands are theoretically larger (20 cards), but those would not be according to basic strategy.
Most hands, player and dealer, are 2 to 4 cards.
If you see a huge hand like that, it will be full of aces, and you should sit out until the next shuffle.
Quote: HunterhillI don't see how you could use 20 cards with three decks?Even totally violating basic strategy.
You're absolutely right. I believe a 20 card hand requires a minimum 5 decks, and to ever see it means that the deck was almost certainly stacked rather than shuffled.
It is entirely possible in a 2 deck (or single deck) game to have one hand take all the aces.
With 3 deck. Player is dealt 2, 2, dealer up-card is 7. Split 2,2 three times. On each 2 you are dealt A,A,A,7,2,2,5 for a total of 21. Then, without violating basic strategy, you are using 32 cards for the player.Quote: HunterhillI don't see how you could use 20 cards with three decks?Even totally violating basic strategy.
Quote: teliotWith 3 deck. Player is dealt 2, 2, dealer up-card is 7. Split 2,2 three times. On each 2 you are dealt A,A,A,7,2,2,5 for a total of 21. Then, without violating basic strategy, you are using 32 cards for the player.
Well, that's a fun mental exercise, no? GJ, teliot! :)
I don't know. I looked at the question and wrote down the answer -- seemed obvious to me.Quote: beachbumbabsWell, that's a fun mental exercise, no? GJ, teliot! :)
The original question is very interesting as an exercise. I think the 2.8 number is just fluff as far as answering the question and I hoped someone would run a sim and get the right answer (to a couple of decimal digits). The game is not symmetric, so 2.8 does not apply equally to the dealer and player in a head's up game. Maybe, someday soon, I'll modify my code and get this answer.
Quote: teliotWith 3 deck. Player is dealt 2, 2, dealer up-card is 7. Split 2,2 three times. On each 2 you are dealt A,A,A,7,2,2,5 for a total of 21. Then, without violating basic strategy, you are using 32 cards for the player.
Thanks... I hadn't even considered splits. Just looking at the maximum a single hand could have.
(I would count that as "4x 8 card hands", not one hand... but that's splitting pairs.)
