pastel23
pastel23
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June 16th, 2014 at 1:57:10 AM permalink
Hi,

I am hoping someone can help.

What's the odds of a dealer getting any 3 seven's in a six deck game with 4 boxes in play?
What's the odds of a dealer getting any 3 red seven's in a six deck game with 4 boxes in play?

Thanks
charliepatrick
charliepatrick
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June 16th, 2014 at 1:27:28 PM permalink
Technically you have to say what the Blackjack rules are as it's possible all four hands have busted or received BJs beforehand. This would need a lot of combinational analysis.

I assume you're actually asking what's the chances of the dealer (or indeed anyone else who hits rather than stands or splits) to receive three sevens. The answer is simply 1/13 * (4D-1)/(52D-1) * (4D-2)/(52D-2) where D is the number of decks. For red sevens use 1/26 then 2D.
AceTwo
AceTwo
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June 17th, 2014 at 12:09:59 PM permalink
Quote: pastel23

Hi,

I am hoping someone can help.

What's the odds of a dealer getting any 3 seven's in a six deck game with 4 boxes in play?
What's the odds of a dealer getting any 3 red seven's in a six deck game with 4 boxes in play?

Thanks


Does not matter how many boxes are in play.
Any 3 sevens is: combin(24,2)/combin(312,2) * 22/310
3 red sevens is: combin(12,2)/combin(312,2) * 10/310
miplet
miplet
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June 17th, 2014 at 2:10:51 PM permalink
Quote: pastel23

Hi,

I am hoping someone can help.

What's the odds of a dealer getting any 3 seven's in a six deck game with 4 boxes in play?
What's the odds of a dealer getting any 3 red seven's in a six deck game with 4 boxes in play?

Thanks


The above two posts are correct assuming you mean only 7 sevens and not hands like 7,2,7,7 or 7,7,A,7
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