bobluered
bobluered
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December 22nd, 2012 at 6:31:22 PM permalink
I understand ev in relation to the coin toss....50/50...= no ev but is the ev in blackjack the result of simulations that show an advantage or disadvantage. Here is an example: One of the "blackjack gurus" recently wrote that with a 2 upcard the player will win 6 times out of 11 times. Does that mean that the ev in 9% on that one hand? If you look at each upcard the house still has a slight advantage.
Ibeatyouraces
Ibeatyouraces
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December 22nd, 2012 at 6:33:44 PM permalink
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DUHHIIIIIIIII HEARD THAT!
bobluered
bobluered
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December 22nd, 2012 at 6:55:25 PM permalink
Then each hand has an individual ev. Another example would be a 10 upcard. With a 10 upcard it is expected that the player will win 5 times out of 12, making the player a 17% underdog. Looking at all cards the house, as I wrote before, has a slight edge. Am I saying this right?
Ibeatyouraces
Ibeatyouraces
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December 22nd, 2012 at 7:03:07 PM permalink
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DUHHIIIIIIIII HEARD THAT!
bobluered
bobluered
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December 22nd, 2012 at 8:40:19 PM permalink
OK...I see what you mean. It is hard for me to think that the upcard is not as important as your hand. As an example, when a 6 is the upcard and we are told that it will bust 42% of the time and you are not supposed to hit your hand after your hand totals hard 12, but I guess the charts take that into consideration. Thank you for helping me understand.
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