November 24th, 2011 at 5:25:30 AM
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Me and the guys were playing pinochle and two of us didn't have a marriage (any king or queen combo of the same suit) on the same deal. We started talking about the odds of this happening.
This is how we play...
80 cards
J-Q-K-10-A only
4 suits
4 of each card
i.e. J-Q-K-10-A x4 in each of the suits.
We deal 20 cards each to all 4 players
Love to know the odds!!
Thanks!!
This is how we play...
80 cards
J-Q-K-10-A only
4 suits
4 of each card
i.e. J-Q-K-10-A x4 in each of the suits.
We deal 20 cards each to all 4 players
Love to know the odds!!
Thanks!!
November 26th, 2011 at 10:49:15 AM
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I estimate the probability of <i>having </i> a marriage in any given hand to be about 98.9% (.989)
Thus, the approximate odds of <i>not </i> having a marriage in two hands is about .012% (.00012)... about 1 time every 10,000 deals.
I'm sure the exact percentages are not off by much.
Thus, the approximate odds of <i>not </i> having a marriage in two hands is about .012% (.00012)... about 1 time every 10,000 deals.
I'm sure the exact percentages are not off by much.