November 13th, 2011 at 7:12:27 AM
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A close family member got a new Cell Phone recently, and I was intrigued by the number. The 7 digit number contains each digit 1 to 7, with the three even digits as the exchange, and the four odd digits as the number (EEE-OOOO). Also, the area code is a combination of the digits 8, 9, and 0. It's a perfect ten digit phone number that uses every digit exactly once. So which do you think is more rare, the fact that the 7 digit number uses 1-7 with the even and odd separated correctly, or that the 10 digit number contains every digit 0 to 9? It's fairly simple math to complete, but it's an interesting one to ponder before you put pencil to paper.
November 13th, 2011 at 7:43:11 AM
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My phone number used to be 222-2239. The digits add up to 22. Very easy to remember.
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November 13th, 2011 at 7:45:32 AM
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Off the top of my head, the 10 digits being used once would be far more difficult than the eee-oooo possibility.
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You want the truth! You can't handle the truth!
November 14th, 2011 at 12:14:19 PM
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eee-oooo has to be rarer. The 0-9 can be in almost any position (0 can't be first), but there are far fewer ways to arrange the three even numbers in three possible positions.
Simplicity is the ultimate sophistication - Leonardo da Vinci