hps
hps
  • Threads: 2
  • Posts: 3
Joined: Apr 29, 2011
April 29th, 2011 at 6:45:44 AM permalink
Hi there, Im new here, and I'm writing because I need some help calculating the return of a bonus feature I am trying to develop.

Basically, the bonus consists on a screen, which have 32 items, and the user will be picking prizes until 3 stoppers appear, Then the bonus ends and the user collects all the prizes he discovered untill now.

the posibilites will be N1 Value1 prizes, N2 Value2 prizes, N3 Value3 prizes, N4 Value4 prizes, NB Blank prizes, and NS Stoppers,
Where N1 + N2 + N3 + N4 + NB + NS = 32

If the chance of hitting this bonus is CH,

how do I calculate the Average return of this feature?
I presumed that the calculation will be guided into founding the avg number of items collected before picking 3 stoppers, and the the average prizes for this number of stones, or is as easy as getting the max prize, the min prize, the total number of possible combinations and do some calculus with that?

Any help will be preciated.
Feel free to ask for more details if something is not clear enough.

Thanks in advance.

HPS.
miplet
miplet
  • Threads: 5
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Joined: Dec 1, 2009
May 7th, 2011 at 2:38:44 AM permalink
1. calculate the probability of winning 0 to total number of prizes (including blank prizes). Well call these xp
p= total number of prizes (including blank prizes)
s = number of stoppers
w = number of prizes won
t = total number of prizes and stoppers (32 in your case)
xp=combin(p,w)*combin(s,2)*(s-2)/combin(t,w+2)/(t-2-w)
(note: if you change the number of stopper until ends to 4 ,replace the four 2's with 3's.)

2. calculate the average prize value.(a)
a=(sum of all prizes)/p

3. the return is the sum of each xp * p *a
I put a spread sheet in google docs
Any questions, just ask.
“Man Babes” #AxelFabulous
hps
hps
  • Threads: 2
  • Posts: 3
Joined: Apr 29, 2011
June 10th, 2011 at 11:36:32 AM permalink
thank you very much! I will put a hand on this right now!
CrystalMath
CrystalMath
  • Threads: 8
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Joined: May 10, 2011
June 10th, 2011 at 2:12:05 PM permalink
I just want to reaffirm that miplet's calculations are correct.
I heart Crystal Math.
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