House Edge
Quote: MathCuriousSuppose we have roulette with 37 numbers including a zero. But every time the ball lands on a zero, the payout ratio is 1:1/2. In a straight up bet with a ratio payout of 35:1. Is the house edge then 35(1/37)-1/2(1/37)-1(35/37)?
If the player loses only half his straight up bet when the ball lands on the zero, then the player's EV would be your number: 35(1/37)-(1/2)(1/37)-1(35/37) = -1/74.
That would make the house edge on the straight up bet 1/74.
Sound like you are talking about the 'La Partage' or 'En Prison' rule.Quote: MathCuriousSuppose we have roulette with 37 numbers including a zero. But every time the ball lands on a zero, the payout ratio is 1:1/2. In a straight up bet with a ratio payout of 35:1. Is the house edge then 35(1/37)-1/2(1/37)-1(35/37)?
The house edge of the even money bets is indeed so improved. BUT only for the even money bets where half the stake is returned on a zero result. Inside bets still have a house edge of 1/37
Quote: MathCuriousSuppose we have roulette with 37 numbers including a zero. But every time the ball lands on a zero, the payout ratio is 1:1/2. In a straight up bet with a ratio payout of 35:1. Is the house edge then 35(1/37)-1/2(1/37)-1(35/37)?
Perhaps I am missing something, but if the "payout ratio is 1:1/2" isn't that the same as 2:1?
Dog Hand
I think he got it the wrong way round. It's half stake returned on losing to a zero.Quote: DogHandPerhaps I am missing something, but if the "payout ratio is 1:1/2" isn't that the same as 2:1?
Dog Hand
