blackorange
blackorange
Joined: Sep 17, 2010
  • Threads: 8
  • Posts: 26
September 30th, 2010 at 12:38:35 PM permalink
Can 6 be taken as a mean average of the ace, ie midway between 1 and 13?

If so, then 2 3 4 5 6 7 8 9 10 10 10 10 + 6 = 91 for the value of deck

91 divided by 13 cards

=

7.

Is 7 the average value likely to arise?

Is 3 cards on average more likely to result in 21 anyway?

thanks for looking!

blackorange
mkl654321
mkl654321
Joined: Aug 8, 2010
  • Threads: 65
  • Posts: 3412
September 30th, 2010 at 1:17:08 PM permalink
Since it will more often be used as an 11-count card than a 1-count, I would think that the mean would be more like 8. If it's initially dealt with a 9, 10, J, Q, or K, it will be counted as 11; with a 7 or 8, it will almost always be counted as 11; with another Ace, it will be counted as 11 (even if it's split and dealt a deuce). And even if it's dealt as part of A2-A6, it will often eventually be counted as 11 rather than 1.
The fact that a believer is happier than a skeptic is no more to the point than the fact that a drunken man is happier than a sober one. The happiness of credulity is a cheap and dangerous quality.---George Bernard Shaw

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