Simple question from stupid guy...
August 17th, 2017 at 6:56:58 PM
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Simple question from stupid guy...
We have
((120*X1)+(80*X2))/(X1+X2)=99
How to find X1 and X2 ?
Is it possible?
But final target is equation with five and more unknowns...
((120*X1)+...+(80*X5))/(X1+... +X5)=99
We have
((120*X1)+(80*X2))/(X1+X2)=99
How to find X1 and X2 ?
Is it possible?
But final target is equation with five and more unknowns...
((120*X1)+...+(80*X5))/(X1+... +X5)=99
August 17th, 2017 at 7:09:32 PM
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Wolframalpha.com
Change X1 to A, X2 to B, etc.
B = -A - 200
Edit, forgot the = 99 part.
http://m.wolframalpha.com/input/?i=%28%28120%2Ba%29%2B%2880%2Bb%29%29%2F%28a%2Bb%29+%3D+99&x=0&y=0
B = (100 - 49A)/49
Change X1 to A, X2 to B, etc.
B = -A - 200
Edit, forgot the = 99 part.
http://m.wolframalpha.com/input/?i=%28%28120%2Ba%29%2B%2880%2Bb%29%29%2F%28a%2Bb%29+%3D+99&x=0&y=0
B = (100 - 49A)/49
August 17th, 2017 at 7:17:17 PM
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Thank you for link.
I think I need to remember the elementary school math course...
I think I need to remember the elementary school math course...
August 17th, 2017 at 7:24:08 PM
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You use ((120+a)+(80+b))/(a+b) = 99
But that was correct
((120*a)+(80*b))/(a+b) = 99
BUT THANKS ANYWAY
Your link will save more hours of my lifetime)))
But that was correct
((120*a)+(80*b))/(a+b) = 99
BUT THANKS ANYWAY
Your link will save more hours of my lifetime)))
August 17th, 2017 at 7:36:21 PM
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Damnit I messed it up twice, forgetting the =99 as well as thinking those were + signs not *'s.
But I think you figured it out -- just plug in formula and it'll give you proper result.
But I think you figured it out -- just plug in formula and it'll give you proper result.
