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Wizard
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Wizard
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April 28th, 2016 at 5:23:58 PM permalink
Two aircraft carriers fire missiles at each other at the same time (like in the movie The Spy Who Loved Me). However, the two missiles travel at different speeds, and do not hit each other in mid air. There is no wind and they follow the same trajectory, other than not hitting each other. After crossing each other, it takes 10 more minutes for missile A to reach its target. 90 minutes after the mid-air crossing, missile B reaches its target.

What is the ratio of the speed of missile A to missile B?
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ChesterDog
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April 28th, 2016 at 6:28:32 PM permalink
Quote: Wizard

Two aircraft carriers fire missiles at each other at the same time (like in the movie The Spy Who Loved Me). However, the two missiles travel at different speeds, and do not hit each other in mid air. There is no wind and they follow the same trajectory, other than not hitting each other. After crossing each other, it takes 10 more minutes for missile A to reach its target. 90 minutes after the mid-air crossing, missile B reaches its target.

What is the ratio of the speed of missile A to missile B?



Let t = minutes from launch to mid-air crossing, a = missile A's speed, and b = missile B's speed. Then:
a * t = b * 90 because the distance traveled by missile A before mid-air crossing equals the distance traveled by missile B after mid-air crossing.
b * t = a * 10 because the distance traveled by missile B before mid-air crossing equals the distance traveled by missile A after mid-air crossing.
Solve each equation for t and equate: t = b * 90 / a = a * 10 / b.
Then a2 = 9 * b2; a = ±3 * b.
beachbumbabs
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April 28th, 2016 at 6:29:31 PM permalink
Quote: Wizard

Two aircraft carriers fire missiles at each other at the same time (like in the movie The Spy Who Loved Me). However, the two missiles travel at different speeds, and do not hit each other in mid air. There is no wind and they follow the same trajectory, other than not hitting each other. After crossing each other, it takes 10 more minutes for missile A to reach its target. 90 minutes after the mid-air crossing, missile B reaches its target.

What is the ratio of the speed of missile A to missile B?



I'm having trouble with the idea that two missiles traveling same distance, same trajectory, could be at such different speeds to one another. 8:1? Not really a spoiler 'cuz it can't be right. One is a cannonball, the other a cruise missile, at least in my head.
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ThatDonGuy
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April 28th, 2016 at 6:33:18 PM permalink

Let DA be the distance from missile A's launch point to the near-miss point
DB the distance from B's launch point to the near-miss point
VA and Vb the velocities of missiles A and B

It took the same time for missile A to travel distance DA as for B to travel DB:
DA / VA = DB / VB
It took 10 minutes for missile A to travel distance DB:
DB = VA x 10
It took 90 minutes for missile B to travel distance DA:
DA = VB x 90

DA / VA = (VB x 90) / VA
DB / VB = (VA x 10) / VB
Since DA / VA = DB / VB, (VB * 90) / VA = (VA x 10) / VB
VB2 x 90 = VA2 x 10
9 VB2 = VA2
(3 VB)2 = VA2
3 VB = VA
VA / VB = 3

MathExtremist
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April 28th, 2016 at 6:36:12 PM permalink
Edit: nevermind, I totally blew it. That's what I get for trying to answer math puzzles after drinking wine.
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BleedingChipsSlowly
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April 28th, 2016 at 6:49:54 PM permalink
Quote: beachbumbabs

I'm having trouble with the idea that two missiles traveling same distance, same trajectory, could be at such different speeds to one another. 8:1? Not really a spoiler 'cuz it can't be right. One is a cannonball, the other a cruise missile, at least in my head.



...they are space ships? Does that work for you?


I used different equations than ChesterDog, but wound up with the same type of equation to solve. Took me a few goes at the problem logic to get there.
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Johnzimbo
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April 28th, 2016 at 7:48:50 PM permalink
If the missiles are North Korean they wouldn't reach their destination
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