Arnie
Arnie
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December 12th, 2015 at 7:54:29 PM permalink
Which set of numbers contain the most balance of the group: Not sure if there is a correct answer but just need to read what people say, thanks


A - 114/60
B - 73/96
C - 78/102
D - 74/92
E - 88/81
F - 123/74
G - 85/79
H - 95/88
RS
RS
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December 12th, 2015 at 7:59:06 PM permalink
Wtf? Idk, maybe G
muleyvoice
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December 12th, 2015 at 8:02:56 PM permalink
A of course
TomG
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December 12th, 2015 at 8:16:49 PM permalink
E

Your post is too short
Arnie
Arnie
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December 12th, 2015 at 8:31:27 PM permalink
Quote: TomG

E

Your post is too short



I know, sorry

but why would you say E versus G ?
TomG
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December 12th, 2015 at 8:41:37 PM permalink
It is the only one with the same digit on both sides of the / creating more balance than any of the others
Arnie
Arnie
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December 12th, 2015 at 8:45:48 PM permalink
Quote: TomG

It is the only one with the same digit on both sides of the / creating more balance than any of the others



interesting, thank you
MathExtremist
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December 12th, 2015 at 9:32:14 PM permalink
Indefinite. You need to define balance first, at least in this context.
"In my own case, when it seemed to me after a long illness that death was close at hand, I found no little solace in playing constantly at dice." -- Girolamo Cardano, 1563
TwoFeathersATL
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December 13th, 2015 at 4:43:44 AM permalink
A and D are both balanced, so it's a tie.

<Edit> upon further review, D is slightly more balanced than A.
Go with D.

If you on some rare occasion you find yourself following 2F's logic fully, then you should ask a question of yourself.
Question = "Should I be worried now?"
Youuuuuu MIGHT be a 'rascal' if.......(nevermind ;-)...2F
Dalex64
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December 13th, 2015 at 7:02:17 AM permalink
Quote: MathExtremist

Indefinite. You need to define balance first, at least in this context.



I agree. Most balanced how?
Arnie
Arnie
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December 13th, 2015 at 7:40:29 AM permalink
Quote: TwoFeathersATL

A and D are both balanced, so it's a tie.

<Edit> upon further review, D is slightly more balanced than A.
Go with D.

If you on some rare occasion you find yourself following 2F's logic fully, then you should ask a question of yourself.
Question = "Should I be worried now?"



why ?
OnceDear
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December 13th, 2015 at 8:59:53 AM permalink
Quote: Arnie

Quote: TwoFeathersATL

A and D are both balanced, so it's a tie.

<Edit> upon further review, D is slightly more balanced than A.
Go with D.

If you on some rare occasion you find yourself following 2F's logic fully, then you should ask a question of yourself.
Question = "Should I be worried now?"



why ?

Arnie, A word to the wise: If you ask meaningless questions, you will get meaningless answered based on meaningless analysis.
Psalm 25:16 Turn to me and be gracious to me, for I am lonely and afflicted. Proverbs 18:2 A fool finds no satisfaction in trying to understand, for he would rather express his own opinion.
Arnie
Arnie
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December 13th, 2015 at 9:11:02 AM permalink
ok lets say each side is weights on a bench press bar
TwoFeathersATL
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December 13th, 2015 at 9:40:14 AM permalink
To Once Dear,
You might be a bad man, not sure..?
To Arnie, did you consider the numbers, the sets, the divider, the equation or quotient or lack there-of?
The answer appeared thru the fog, then the fog lifted and I saw the light.
Prolly wrong answer, but what the hell?
Was a pretty slow Sunday morning.......
Youuuuuu MIGHT be a 'rascal' if.......(nevermind ;-)...2F
MathExtremist
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December 13th, 2015 at 10:50:41 AM permalink
Quote: Arnie

ok lets say each side is weights on a bench press bar

Each side? That means your original post wasn't about fractions.

If you assume the weights are in kg and take into account the 20-kg weight of the bar, you can determine which set of weights yield a center of mass closest to the center of the bar. You also need to assume a normal loading scheme, nothing screwy like putting the heavy plates further away.

In other words, with enough additional detail, the concept of balance makes sense.
"In my own case, when it seemed to me after a long illness that death was close at hand, I found no little solace in playing constantly at dice." -- Girolamo Cardano, 1563
Arnie
Arnie
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December 13th, 2015 at 12:35:27 PM permalink
Quote: MathExtremist

Each side? That means your original post wasn't about fractions.

If you assume the weights are in kg and take into account the 20-kg weight of the bar, you can determine which set of weights yield a center of mass closest to the center of the bar. You also need to assume a normal loading scheme, nothing screwy like putting the heavy plates further away.

In other words, with enough additional detail, the concept of balance makes sense.



Yes each side. Assuming kg and 20 kg weight of bar and nothing screwy nothing screwy

You would say G 85/79 would be the most balanced compared to the other examples?
RS
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December 13th, 2015 at 12:40:43 PM permalink
What is the purpose of this?
OnceDear
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December 13th, 2015 at 2:15:03 PM permalink
Quote: TwoFeathersATL

To Once Dear,
You might be a bad man, not sure..?


Bad? Noooooo. I'm one of the good guys. . . . Mostly.
Psalm 25:16 Turn to me and be gracious to me, for I am lonely and afflicted. Proverbs 18:2 A fool finds no satisfaction in trying to understand, for he would rather express his own opinion.
TwoFeathersATL
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December 13th, 2015 at 2:35:20 PM permalink
Quote: RS

What is the purpose of this?

I thought you were supposed to laugh, that's all I could think of..

Time goes on, tick tock, might have been a question relating to 'toss out some question to a bunch of mathelites or gamblers, a question that can't be answered correctly, and watch them try. Might be a homework assignment due Monday. Prolly not, but maybe.......

Try this:
Add the digits on the right side of the assumed separator symbol to obtain a sum, and compare that sum to the sum of the digits on the left side of the separator symbol for a measure of balance. With me?
A and D tie, looked like tie. But the instructions said pick 'the most balanced'.
Back to drawing board, more chalk....
Sums equal for A and D, but A has 3 digits to the left, only 2 for the right.
We were looking for one choice...
The weight of each digit comes into play, in the sets A vs D, and A has 3 digits to add for a balanced sum on the left, but only 2 on the right.
Now everyone knows that to break a tie you have to consider other tie breaking factors. 3 digits to left vs 2 digits to the right for choice A. 2 vs 2 for choice D. Digits must have some weight, not just value. Therefore:

D most balanced.

Of course there are other solutions available depending on level of sobriety, and numerous other factors, assumptions, and/or conditions.
Youuuuuu MIGHT be a 'rascal' if.......(nevermind ;-)...2F
charliepatrick
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December 13th, 2015 at 3:26:35 PM permalink
Quote: Arnie

Which set of numbers contain the most balance of the group: Not sure if there is a correct answer...G - 85/79...

It reminds me of a university-entrance question "Is This A Question?".

My guess on the answer is G since you have 8kg at 2m and 5kg at 1m compared with 7kg at 1m and 9 kg at 2m. By pure co-incidence it is also the closest as 85/79 = 1.075949 which is the nearest to 1 (H is 1,07955) - so another answer might be G is very close to H.

btw I heard the best answer to the other question, was Yes - if this is an answer.
Arnie
Arnie
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December 13th, 2015 at 7:39:56 PM permalink
Quote: TwoFeathersATL

I thought you were supposed to laugh, that's all I could think of..


Try this:
Add the digits on the right side of the assumed separator symbol to obtain a sum, and compare that sum to the sum of the digits on the left side of the separator symbol for a measure of balance. With me?
A and D tie, looked like tie. But the instructions said pick 'the most balanced'.
Back to drawing board, more chalk....
Sums equal for A and D, but A has 3 digits to the left, only 2 for the right.
We were looking for one choice...
The weight of each digit comes into play, in the sets A vs D, and A has 3 digits to add for a balanced sum on the left, but only 2 on the right.
Now everyone knows that to break a tie you have to consider other tie breaking factors. 3 digits to left vs 2 digits to the right for choice A. 2 vs 2 for choice D. Digits must have some weight, not just value. Therefore:

D most balanced.

Of course there are other solutions available depending on level of sobriety, and numerous other factors, assumptions, and/or conditions.




ok this is interesting for what i'm testing

Thank you!
muleyvoice
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December 13th, 2015 at 7:47:09 PM permalink
The only correct answer is still A.
TwoFeathersATL
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December 13th, 2015 at 8:30:59 PM permalink
Quote: Arnie

ok this is interesting for what i'm testing

Thank you!

Tell me you don't work for the government, my government.
I own part of it....
Youuuuuu MIGHT be a 'rascal' if.......(nevermind ;-)...2F
TwoFeathersATL
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December 13th, 2015 at 8:42:09 PM permalink
Quote: muleyvoice

The only correct answer is still A.


I cannot find A as balanced, MV.
Can you help me?

Yes, question begs for joke, fire away

Of course RS had best answer, and right off the bat.
I respect RS more now, in spite of that jumpy avatar thing. Typed thong by accident. Spell check to the rescue..
RS's jumpy thong would have been funny though........
Youuuuuu MIGHT be a 'rascal' if.......(nevermind ;-)...2F
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