Poker Dice, Aces wild, Flushes and straights don't count
July 8th, 2010 at 9:20:45 PM
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No big deal - A friend got into an argument...
Poker Dice - marked 9,10,J,Q,K,A.
Traditionally I get 6 5kind, 150 4kind, 240 straight, 300 Full house, high card 480, 3kind 1200, 2pair 1800, 1pair 3600,
for a total of 7776 hands.
It's only on a come-out roll. The rules from "normal" are: Aces are wild and flushes and straights do not exist.
How far off am I in adjusting my original numbers to 156 5kind, 1300 4kind, 3500 3kind, 900 2pair, 1680 1pair, king high 240?
Poker Dice - marked 9,10,J,Q,K,A.
Traditionally I get 6 5kind, 150 4kind, 240 straight, 300 Full house, high card 480, 3kind 1200, 2pair 1800, 1pair 3600,
for a total of 7776 hands.
It's only on a come-out roll. The rules from "normal" are: Aces are wild and flushes and straights do not exist.
How far off am I in adjusting my original numbers to 156 5kind, 1300 4kind, 3500 3kind, 900 2pair, 1680 1pair, king high 240?
July 9th, 2010 at 8:57:30 AM
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Here are my aces wild outcomes and how they are made:
5 of a kind: 156
5 aces: 1
1 ace, 4 of a kind: 25
2 aces, three of a kind: 50
3 aces, pair: 50
4 aces, other: 25
5 of a kind: 5
4 of a kind: 1300
3 aces, 2 others: 400
2 aces, pair, other: 600
1 ace, three of a kind, other: 200
4 of a kind, other: 100
Fullhouse: 800
ace, 2 pairs: 600
three of a kind, pair: 200
3 of a kind: 1800
2 aces, 3 others: 600
1 ace, pair, 2 others: 600
3 of a kind, 2 others: 600
2 pairs: 1800
2 pairs, other: 1800
1 pair: 1800
pair, 3 others: 1200
ace, 4 others:600
King high: 120
5 others: 120
5 of a kind: 156
5 aces: 1
1 ace, 4 of a kind: 25
2 aces, three of a kind: 50
3 aces, pair: 50
4 aces, other: 25
5 of a kind: 5
4 of a kind: 1300
3 aces, 2 others: 400
2 aces, pair, other: 600
1 ace, three of a kind, other: 200
4 of a kind, other: 100
Fullhouse: 800
ace, 2 pairs: 600
three of a kind, pair: 200
3 of a kind: 1800
2 aces, 3 others: 600
1 ace, pair, 2 others: 600
3 of a kind, 2 others: 600
2 pairs: 1800
2 pairs, other: 1800
1 pair: 1800
pair, 3 others: 1200
ace, 4 others:600
King high: 120
5 others: 120
“Man Babes” #AxelFabulous
July 9th, 2010 at 3:53:14 PM
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Hi miplet
Much thanks for your reply. I am embarrassed that I misspoke my own question on my first post. I think in really big letters too to make it worse lol.
I meant to say "no full houses" rather than "no flushes".
Anyway, it's no full houses, no straights and, I guess, no flushes either lol. With Aces wild.
It's OK if you do not redo your numbers. Completely my fault.
Much thanks for your reply. I am embarrassed that I misspoke my own question on my first post. I think in really big letters too to make it worse lol.
I meant to say "no full houses" rather than "no flushes".
Anyway, it's no full houses, no straights and, I guess, no flushes either lol. With Aces wild.
It's OK if you do not redo your numbers. Completely my fault.
July 9th, 2010 at 6:20:14 PM
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Quote: Curiousguy11Hi miplet
Much thanks for your reply. I am embarrassed that I misspoke my own question on my first post. I think in really big letters too to make it worse lol.
I meant to say "no full houses" rather than "no flushes".
Anyway, it's no full houses, no straights and, I guess, no flushes either lol. With Aces wild.
It's OK if you do not redo your numbers. Completely my fault.
There's nothing to redo. Just count the fullhouses as 3 of a kind.
“Man Babes” #AxelFabulous
July 12th, 2010 at 10:05:08 PM
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Thanks again, miplet.
I'll give one last try at what, very very likely, I realize, is my problem.
It just, maybe, seems to me, if Aces were not wild in the first place and full houses (and straights) (but no flushes)would have been counted then, one would only have had 300 full houses to re-allocate once Aces became wild.
Like maybe, 100 of the 5-kinds you already counted in your 156 (the other 50 possibly coming from re-allocating the orig 150 4kinds when aces were not wild), were from full houses after Aces became wild. And maybe another 200 of originalfull houses, no aces wild, would go to 3-kinds when aces became wild?
Anyway, I also was trying to re-allocate 240 straights before aces became wild. Likewise, 1800 2pair and 3600 1pair while counting full-houses and straights (no aces wild) in original possibilities.
You're probably doing it the right way, with math, and I'm doing it the hard way - a little, likely, misapplied math and a little brute force lol.
If aces originally were not wild and full houses and straights would count ( but no flushes ever!) are my original probabilities at least OK as a starting point?
Basically, I have no business posting in a math section but I like to try to figure stuff out.
I'll give one last try at what, very very likely, I realize, is my problem.
It just, maybe, seems to me, if Aces were not wild in the first place and full houses (and straights) (but no flushes)would have been counted then, one would only have had 300 full houses to re-allocate once Aces became wild.
Like maybe, 100 of the 5-kinds you already counted in your 156 (the other 50 possibly coming from re-allocating the orig 150 4kinds when aces were not wild), were from full houses after Aces became wild. And maybe another 200 of originalfull houses, no aces wild, would go to 3-kinds when aces became wild?
Anyway, I also was trying to re-allocate 240 straights before aces became wild. Likewise, 1800 2pair and 3600 1pair while counting full-houses and straights (no aces wild) in original possibilities.
You're probably doing it the right way, with math, and I'm doing it the hard way - a little, likely, misapplied math and a little brute force lol.
If aces originally were not wild and full houses and straights would count ( but no flushes ever!) are my original probabilities at least OK as a starting point?
Basically, I have no business posting in a math section but I like to try to figure stuff out.
