baccarat calculator this web site

Hello
The baccarat calculator found on this web site allows you to remove one or more cards and then calculate the new odds. What I would like to be able to do is calculate the new odds for myself. I am clueless how this done. My question assumes an eight deck shoe. The following is an example in which all the 8's are removed

Outcome Combinations Probability
0.455086
Banker Bet Banker wins 1,402,924,333,975,552 0.455086
Player Bet Player wins 1,370,360,424,040,448 0.444522
Tie Bet Tie 309,485,380,500,480 0.100392
8 to 1
Totals 3,082,770,138,516,480 1.000000


Thanks in advance for any help or insight!
Wackogeorge

Quote: wackogeorge

Hello
The baccarat calculator found on this web site allows you to remove one or more cards and then calculate the new odds. What I would like to be able to do is calculate the new odds for myself. I am clueless how this done. My question assumes an eight deck shoe. The following is an example in which all the 8's are removed

Outcome Combinations Probability
0.455086
Banker Bet Banker wins 1,402,924,333,975,552 0.455086
Player Bet Player wins 1,370,360,424,040,448 0.444522
Tie Bet Tie 309,485,380,500,480 0.100392
8 to 1
Totals 3,082,770,138,516,480 1.000000


Thanks in advance for any help or insight!
Wackogeorge

You mean you want to write your own program? Spreadsheet? Use an abacus?

when I find out how to do it I will write a computer program. I know how to program I just don't know how the combinations for banker, player, tie are figured.

Read this thread . You'll probably have a question or two after reading it like how to score the Banker and Player hands. I can go over that later, but I have work and sleep that must be done first.

to miplet
Thank you so much for your help so far. You are correct I do have a few questions. Of the 3025 possible values for the first four cards I believe there are 1210
values that do not require a third card for either player or banker. I obtained this by modifying the code to play baccarat that I wrote previously. According to the wizard there are 1893735611458560 combinations for four cards. The way I am computing the combinations is as follows ( and it's wrong): For each of the 1210 values that do not require a third card, assuming the players cards are 10 and 10 and the bankers cards are 10 and 8. I do this 128(10's) times 127(10's)times 126(10's) times 32(8's) times 412(third players card not used) times 411(third bankers card not used) and then add the 1210 values together. This equals only 575520161301504, I am more than 1,300,000,000,000,000 combinations short.

player 10,8 banker 5,7 = 128*32*32*32*412*411
player 3,6 banker 4,5 = 32*32*32*32*412*411
(more examples)

Can you tell me how to figure the combinations correctly?
Thanks in advance
Wackogeorge

my bad
I think I found my error!
thank for your interest.