How to calculate the probability of losing 50 more times than wining in bacarrat ?

Hi all,

Actually the question is like this: assuming the bankroll is 5000, and each bet is 100, what is the probability of losing all the bankroll within 2000 bets? i am not sure if the question make sense.

thanks in advance.

Without another constraint, like total number of hands, it should be 100%, right? BAccarat is -EV, so eventually, you're expected to crash out.

To lose 50 bets in Bacc. presuming "Banker" betting takes on average 4735.9 bets: presuming "Player" bets 4048.6 bets.

yes, a constraint is needed, i forget to provide it :(. Thanks for the notice.

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silly


Sally

Quote: ilikevp

Hi all,

Actually the question is like this: assuming the bankroll is 5000, and each bet is 100, what is the probability of losing all the bankroll within 2000 bets? i am not sure if the question make sense.

thanks in advance.

It is your question, but customarily people ask what is the probability of earning 20%, 100%, or 150% before I go bankrupt. For instance some people figure that the gasoline, hotel, and dinner costs $1000, and they want to know what is the possibility of winning back that $1000 before losing their $5000 bankroll.

Most people don't actually count the number of times they play.

I get 43.093% if the 2000 hands include ties and you are always betting on the player.