January 26th, 2013 at 2:12:34 PM
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How would you work out the odds in soccer betting (as a percentage and fractional) on a team to draw that has not drawn in 5 matches? To make it more complicated if you choose 10 teams that had not drawn for 5 matches each if you put one dollar on each what are your chances? Please help maths wizards (could you explain in leyman terms :)
January 26th, 2013 at 2:24:44 PM
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Welcome to the board!
There is no answer to your question, because there is nothing to work with here, statistically. Also from a handicapping perspective, you need much more info to even begin to estimate some wildly inaccurate odds.
In absence of any information however, you may assume a probability of 25% for a draw, or 75% for no draw. (based on English Premier League statistics over the last couple of years)
There is no answer to your question, because there is nothing to work with here, statistically. Also from a handicapping perspective, you need much more info to even begin to estimate some wildly inaccurate odds.
In absence of any information however, you may assume a probability of 25% for a draw, or 75% for no draw. (based on English Premier League statistics over the last couple of years)
January 27th, 2013 at 5:26:05 AM
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Thanks Canyonero.
January 27th, 2013 at 8:57:56 AM
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So the chance of getting a draw is 1 in 3? (win, loose, draw) what are the odds of 5 draws in a row?
January 27th, 2013 at 9:58:27 AM
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Quote: GRPSo the chance of getting a draw is 1 in 3? (win, loose, draw) what are the odds of 5 draws in a row?
IF the odds of a draw are 1 in 3 then the odds of five draws in a row is (1/3) ^5 (1/3 x 1/3 x 1/3 x 1/3 x 1/3) which is 1 out of 243 or 242 to 1 against. Please note that the outcome of a win, a loss, and draw are most certainly not equally likely. To clarify, just because you have three possible outcomes, that doesn't mean that each outcome has a one-third chance.
If the odds of a draw happen to be 1 in 4 then the odds of five draws in a row is (1/4) ^5 (1/4 x 1/4 x 1/4 x 1/4 x 1/4) which is 1 out of 1,024 or 1,023 to 1 against.
Welcome to the forum.
(Note: lose, not loose.)
January 27th, 2013 at 9:59:18 AM
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Well... as Canyonero as pointed out, there's a LOT of missing info to generate any kind of meaningful answer. Unlike roulette from the other thread, soccer is skillbased. Now, assuming we were rolling hypothetical 3-sided dice (each one representing W/L/T), getting the same result 5x in a row would be (1/3)^5, or .4% of the time, or about 1 in 243.
Using Canyonero's estimate of the league statistics indicating a 25% tie, it'd be a (1/4)^5, or .09%, or 1:1024.
But, well, sports teams aren't statistically even. Two evenly matched teams are more likely to result in a tie than, say, the best vs the worst teams in the league.
Using Canyonero's estimate of the league statistics indicating a 25% tie, it'd be a (1/4)^5, or .09%, or 1:1024.
But, well, sports teams aren't statistically even. Two evenly matched teams are more likely to result in a tie than, say, the best vs the worst teams in the league.
January 27th, 2013 at 11:20:37 AM
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Quote: GRPSo the chance of getting a draw is 1 in 3? (win, loose, draw) what are the odds of 5 draws in a row?
Minor nitpick, but very important for odds calculation:
25% = 1 to 3 or 1 in 4
1 in 3 would equal 33.3%
January 27th, 2013 at 11:26:36 AM
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Quote: CanyoneroMinor nitpick, but very important for odds calculation:
25% = 1 to 3 or 1 in 4
1 in 3 would equal 33.3%
Oh geez. It's like 1 to 2 and 1 for 2. Doesn't matter that I'm aware of the difference, I just never see the difference. ><
January 27th, 2013 at 11:37:10 AM
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Cheers guys :) I thought it would be a complicated one. Ive been looking at the score cast sheets at the bookmakers and was going to bet on the draws for better odds than the win/lose ;) Trying to decide the best way to pick out 3 teams to draw from the form guide is tough.