How to calculate the house edge on the craps pass line?

I hate advertising how poor my math skills are, but this forum is the best place to get help with this kind of problem.

I know how the Wizard calculates the house edge on the craps pass line, but I want to do it in table format so I can figure what the house (or player) edge would be if the shooter could influence the probability of getting a 7 on the come-out. The first step is to table-ize the figures assuming fair odds. Doing that, I get:

Throw	Prob.	Pay	EV
2	0.027	-1	-0.02777
3	0.055	-1	-0.05555
7	0.166	+1	-0.16666
11	0.055	+1	-0.05555
12	0.027	-1	-0.02777
all other	0.67	-0.458	-0.30572
			-0.19

I figured the "all other" pay by using the 9648/35640 chance of winning a point once it's been established (from the Wizard's craps appendix). -1 x 9468/35640 + 1 x 26172/35640.

Anyway, my result of a house edge of -0.19 doesn't come close to the true house edge of -1.41%. How did I err?

You will lose once the point is established 14112/35640
I have a copy of my custom craps ev in google docs here

also a table from WinCraps


The fraction, instead of -0.0141, should sum to -28/1980 (-7/495)

For those that do not want to deal with fractions and decimals
Here is the perfect 1980 table
(all fractions are multiplied by 55/55
example: 6/36 for the 7 becomes 6/36 * 55/55 = 330/1980)

Event	Freq.	Line Bet	Total Line	Odds Bet	Total Odds	Line Pay	Odds Pay
Natural 7	330	1	330	0	0	330	0
Natural 11	110	1	1100	0	0	110	0
Craps	220	1	220	0	0	-220	0
4 Made	55	1	55	0	0	55	0
4 Not	110	1	110	0	0	-110	0
5 Made	88	1	88	0	0	88	0
5 Not	132	1	132	0	0	-132	0
6 Made	125	1	125	0	0	125	0
6 Not	150	1	150	0	0	-150	0
8 Made	125	1	125	0	0	125	0
8 Not	150	1	150	0	0	-150	0
9 Made	88	1	88	0	0	88	0
9 Not	132	1	132	0	0	-132	0
10 Made	55	1	55	0	0	55	0
10 Not	110	1	110	0	0	-110	0
Totals -	1980	xxx	1,980	xxx	0	-28	0
					1,980	-0.014141414	-28
					handle	house edge	net loss

HA = -28/1980 (-7/495)
examples:
Probability of a come out roll 7 is 330/1980 (1/6)
Probability of a come out roll decision is (330+110+220)/1980 = 1/3

Okay, my mistake was when the Wizard wrote, "The probability of establishing a point and then winning...", I read that as, "The probability of winning a point that's established."

Thanks for the help!