Craps betting question

If I'm at a $10.00 craps table and for example, I have a $12.00 place bet on the 6 and the 8 and a $10 come bet with $10 odds bet on the 5, can I increase my place bets by $6.00 and odds bet by $5.00 or would they have to be increased by $12.00 and $10.00 respectively??? If so, is that a standard or is it up to the dealers that would allow that if for example there is little action at the table???

For the 6/8 place bets, increments of $1 should be allowed over the minimum of $10. Increments of $6 over a minimum wager of $12 is rational behavior, since other increments would pay out short. No need to increase in increments of $12.

Odds bets can also be increased in increments of $1 up to the maximum, but rational behavior says to wager odds on the 5 in even dollar amounts.

Quote: Clownkeeper

If I'm at a $10.00 craps table and for example, I have a $12.00 place bet on the 6 and the 8 and a $10 come bet with $10 odds bet on the 5, can I increase my place bets by $6.00 and odds bet by $5.00 or would they have to be increased by $12.00 and $10.00 respectively??? If so, is that a standard or is it up to the dealers that would allow that if for example there is little action at the table???

The short answer is YES you can increase you 6 and 8 by $6 dollars. and your odds bets by 5. Just think of it this way.....Lets say you have a $12 place bet on the 6 and you win the dealer could pay the $14 win and give you your $12 dollar bet back(for a total of $26). The you could make a $18 place bet on the 6. This is no different then you pressing back $6 dollars of your winnings back on the 6 or 8. The same goes for odds bets

Although if you had $10 worth of odds on the 5 already you would always increase in $10 increments. as $15 of odds on the 5 would pay $22.50 and they will not pay out the 50 cents( in 99% of casinos) So it would not be worth it.

the thing on the free odds on 5 or 9 either one is to have it divisible by two, so if you had a $10 free odds bet on the 5, you wouldnt want to add a dollar, but could add two dollars I think. Most people would add another another $10 of course, to keep from being silly.

Whats that ditty about: Odds on an Odd Number should always be EVEN. This avoids "breakage" wherein you get paid a proper payout on part of your bet but a lesser payout on some it. I leave it to better mathematicians to explain this confusing stuff better.

The "ditty" is only five words: Odds are even on odd.

The mathematical reason is simple: It pays $3 for every $2.

In other words, it pays $1.50 per dollar bet. But, since most craps tables do not have 50¢ or 25¢ chips or coins, you'll lose that last 50¢ when they pay off an odd bet.