painlesswon
painlesswon
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Joined: Jan 12, 2012
February 25th, 2013 at 7:28:47 PM permalink
PLEASE CONSIDER THE FOLLOW:
IF YOU HOLD TEEN WONG AND ZERO, AND ARE BANKING, ACCORDING TO YOUR CALCULATOR, YOUR LOSS IS 16.6% .
LOGIC THEN SAYS THE PLAYER WILL HAVE ANY PAIR, AND CONDITIONS THAT HE DOSE NOT SPLIT THAT PAIR, FOR THE BANK TO LOSE AT 16.6%.
ACCORDING TO ONE OF YOUR TABLES, PAIR FREQUENCY IS 15.1%
HOW DO YO EXPLAIN THIS DISCREPANCY , THAT THE LOSS % IS HIGHER THAN PAIR FREQUENCY, ESPECIALLY IN LIGHT THAT THE OPPONENT WILL SPLIT PAIRS A SIGNIFICANT PERCENTAGE OF HANDS WITH PAIRS.

REGARDS PAINLESSWON

I'M NOT ADDICTED TO TILES, NOR UTH, I JUST LIKE SITTING AT A SEMICIRCULAR TABLE WITH THESE GAMES IN PROGRESS!
JB
Administrator
JB
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Joined: Oct 14, 2009
February 25th, 2013 at 7:32:35 PM permalink
If you remove 4 known tiles from the deck and then pick 4 from the remaining 28, the odds are different than picking 4 tiles from 32, hence the apparent "discrepancy."
painlesswon
painlesswon
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Joined: Jan 12, 2012
February 25th, 2013 at 7:52:20 PM permalink
thank you for the swift reply.....

Yes...the fact that I (the bank) hold four non-paired singletons, makes opponent pair frequency less (pairs make pairs, non pair makes non pairs ) ..... but I believe it would be a small change , and far outweighs the frequency which opponent would split a random pair so that zero wong dose not lose.

So I still can't resolve why you lose 16.8%. It doesn't add up for me intuitively. I'm sorry if I am dense on this.
I guess it could add up to explain the "discrepancy" if I knew the change in pair frequency with one hand known not to hold a pair, and the frequency of splitting a pairs, in a hand holding a random pair.

regards Painlesswon
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