ultimate texas holdem

hi,

i've recently started playing ultimate texas holdem and I have a thought about the game.

What if I play it with my friends and we show ourselves cards? Then we have more information about the game. Does the game become beatable if we know more cards? Lets say we play as 5 -> then we know 10 cards. How does the math work in this case?

Stephen How has an excellent site on this.

practical-collusion-for-ultimate-texas-holdem

My article on this question ...
https://www.888casino.com/blog/novelty-games/ultimate-texas-holdem-collusion

Quote: gordonm888

Stephen How has an excellent site on this.

practical-collusion-for-ultimate-texas-holdem
link to original post

With the added collusion, can we overcome the house advantage?

What I notice about this game is that a lot of dealers make mistakes when paying players. That is explorable.

I have a UTH question and didn't know where to put it, but this seemed like a reasonable place. I'm planning to play UTH for the first time for real during an AC trip next weekend and want to make sure I understand it. I've been using the WOO practice game and it's helpful.

The WOO strategy for the 2x flop decision says:

Medium Raise: Make the 2X raise with any of the following:

[Condition 1] Two pair or better.
[Condition 2] Hidden pair*, except pocket deuces.
[Condition 3] Four to a flush including a hidden 10 or better to that flush

* Hidden pair = Any pair with at least one card in your hole cards (thus the pair is hidden to the dealer).

I think the wording of Condition 1 is a bit unclear. When it says "Two pair or better" that assumes you're using one of your hole card, right? E.G., if you have 2/3 and the flop is QQQ, you should NOT make the 2x bet even though three of a kind is better than 2 pair. It's a bit unclear because Condition 2 and Condition 3 explicitly refer to using at least one of your hole cards, but Condition 1 does not.

If I'm reading it correctly, I think the first two conditions above collapse into one (I think). I believe it means, "Make the 2x bet if you have a pair or better using at least one of your cards, with the only exception being do not make the 2x raise if your holding is exactly 2/2 and you didn't improve on the flop." Is that right? Basically, if I have 2 cards that are not the same rank and at least 1 of them makes a pair, make the 2x bet, right? E.G., My cards are 2/3 and the flop is KQ2, bet 2x?

Yes, I think you spotted the only exception to rule 1. If you have a 2-3 in the hole and the flop comes Q-Q-Q, then obviously you should not raise

Yes, I think you spotted the only exception to rule 1. If you have a 2-3 in the hole and the flop comes Q-Q-Q, then obviously you should not raise

It also comes down to how you understand Wizard’s basic strategy. If you the player have two pairs or better (not the board), then rule #1 will be correct in any circumstances. When there is a trips board, you should raise when you have a second nut kicker.