November 30th, 2012 at 3:53:46 AM
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Can someone help me with the following probability calculations?
Using a standard 52 card deck of cards, and dealing three cards from the deck. What are the probabilities of being dealt no face cards, one face card, two face cards or three face cards?
Using a standard 52 card deck of cards, and dealing three cards from the deck. What are the probabilities of being dealt no face cards, one face card, two face cards or three face cards?
November 30th, 2012 at 4:58:53 AM
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Here's a generic solution:
n=number of face cards received
p=combin(12,n)*combin(40,3-n)/combin(52,3)
n=number of face cards received
p=combin(12,n)*combin(40,3-n)/combin(52,3)
I heart Crystal Math.
November 30th, 2012 at 6:14:52 AM
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Thanks Crystal, I was forgetting the 3-n part...