Buzzard
Buzzard
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January 7th, 2013 at 12:44:19 PM permalink
As a math illiterate I am hoping someone is bored or likes a challenge. The answers may be obvious, but not to me.

5 players playing Basic, single deck, S17, no surrender, DAS. How many times in 1000 hands will the following occur ?

I player bust 2 players bust 3 players bust 4 players bust All 5 players bust

Hopefully that was the easier question

Counting a BJ as 21, how many times will players tie, on totals from 12 to 21 ?

And numbers of players involved in any tie ?

All I can offer as far as financials payment is a hardy handclasp and dinner in Vegas ! Wish it could be more.
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
Buzzard
Buzzard
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January 7th, 2013 at 1:04:59 PM permalink
I know I am dumb and this proves it. On the bust question, do not consider the player to have busted if he still has a live hand
after splitting and busting one or more hands.

Now I know I have no chance of figuring this out !
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
odiousgambit
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January 7th, 2013 at 1:22:42 PM permalink
not easy questions to answer methinks, Buzz
the next time Dame Fortune toys with your heart, your soul and your wallet, raise your glass and praise her thus: “Thanks for nothing, you cold-hearted, evil, damnable, nefarious, low-life, malicious monster from Hell!”   She is, after all, stone deaf. ... Arnold Snyder
Buzzard
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January 7th, 2013 at 1:27:59 PM permalink
Quote: odiousgambit

not easy questions to answer methinks, Buzz




MEKNOWS
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
sodawater
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January 7th, 2013 at 2:04:48 PM permalink
deleted
Last edited by: sodawater on Oct 1, 2018
rdw4potus
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January 7th, 2013 at 2:07:25 PM permalink
Quote: sodawater

I can tell you that the players will tie on 12-16 0 times out of 1000.



Why?

Edit:

Player 1:9-5
Player 2:9-5
Player 3:8-6
Player 4:10-4
Player 5:10-4
Dealer:6

Who's going to hit their 14??
"So as the clock ticked and the day passed, opportunity met preparation, and luck happened." - Maurice Clarett
Buzzard
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January 7th, 2013 at 2:09:51 PM permalink
WHAT ??
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
Buzzard
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January 7th, 2013 at 2:59:37 PM permalink
I am so lost
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
rdw4potus
rdw4potus
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January 7th, 2013 at 3:04:46 PM permalink
Quote: Buzzard

I am so lost



Between the mountain air and your advanced age, that's expected;-)

Honestly, I have no idea how to answer your questions, but I'm certain that the answers are positive non-zero numbers.
"So as the clock ticked and the day passed, opportunity met preparation, and luck happened." - Maurice Clarett
Buzzard
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January 7th, 2013 at 10:48:40 PM permalink
Trust me, I am just as dumb at sea level !
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
Buzzard
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January 8th, 2013 at 8:21:13 AM permalink
Evidently this is not an easy question Sigh
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
chefphydeaux
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January 8th, 2013 at 8:28:49 AM permalink
Quote: sodawater

I can tell you that the players will tie on 12-16 0 times out of 1000.



yeap. player may or may not hit those stiffs. the dealer will always hit those stiffs. end result= no push on 12-16's.
boymimbo
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January 8th, 2013 at 8:29:20 AM permalink
You can only tie on hands where you reach 17-21. You can't tie where you stand on hands below 17, silly!!!

The question is hard because there's no WOO tables that show the odds of busting for single hand blackjack and take the effects of card removal. Therefore, you would have to figure out what the odds are of busting. I think these are readily calculable. When you add other players to the equation, you have to take card removal into account. Certainly if two players have 14 against a dealer 10, both will need to hit, but the odds of busting change considerably vs all of the other cards on the table. This is not easily calculable.
----- You want the truth! You can't handle the truth!
Buzzard
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January 8th, 2013 at 8:34:13 AM permalink
I am talking about ties among the players. They can easily tie and often do when the dealers shows a 2 thru 6.
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
Buzzard
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January 8th, 2013 at 8:35:34 AM permalink
I will settle for any Wild Ass Guesses at this point in time !
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
7craps
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January 8th, 2013 at 8:46:22 AM permalink
Quote: Buzzard

As a math illiterate I am hoping someone is bored or likes a challenge. The answers may be obvious, but not to me.

5 players playing Basic, single deck, S17, no surrender, DAS. How many times in 1000 hands will the following occur ?

I player bust 2 players bust 3 players bust 4 players bust All 5 players bust

Hopefully that was the easier question

Say sim data shows a BS player busting 16% of the time.
You could just say .16^N or just a binomial distribution instead.
but this assumes independence between players at the same table.
I do not think this is true.

CVData does not have this available.

I have a BJ program that tracks player busts per hands and sessions but currently does not track per round the player bust distribution.

I just got the new WinCraps Pro Multi-Player version and am working with it.
Nice.
BJ does not seem that interesting to me at this moment in time.

My BJ program code would have to be changed and I have no interest in it at the moment.

The distribution would be interesting to see BTW, just IMO

The Wizard should really jump at this Q
He could quickly code it up for simulation, maybe even offer the code for $$$ or have JB write an app
and be the 1st to show the distribution

Otherwise, just use the kitchen table and deal the cards.
tabulate the results
I would watch that video

Good Luck!
winsome johnny (not Win some johnny)
Buzzard
Buzzard
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January 8th, 2013 at 11:28:08 AM permalink
Maybe I will log onto math problems ?
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
Buzzard
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January 8th, 2013 at 1:16:11 PM permalink
No help there. GRRR getting frustrated.
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
tringlomane
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January 8th, 2013 at 1:20:58 PM permalink
I don't think this could be solved analytically, or at least not very easily. It would be best to simulate a bunch of 1000-hand samples and tally the results.

It would definitely take more than a handshake and dinner for payment for virtually anyone on this forum, I'd think.
Buzzard
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January 8th, 2013 at 1:49:30 PM permalink
I understand that. But I was hoping for at least a WAG or something to the effect of how reliable a 1000 hand trial might be.
Lot of hands, but not sure it would have any real accuracy !
Shed not for her the bitter tear Nor give the heart to vain regret Tis but the casket that lies here, The gem that filled it Sparkles yet
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