mrjjj
mrjjj
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December 15th, 2010 at 7:12:32 PM permalink
This is a bit of a tough question. I'm wondering what your AVERAGE is per spin, how many numbers bet? I understand it might depend on what method you are playing etc. but try and post an average if you could. There is no wrong answer guys.

Thanks, Ken
Martin
Martin
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December 16th, 2010 at 12:41:39 PM permalink
My average is 0 - I am an outside bettor exclusively - red/black, high/low, even/odd.
mrjjj
mrjjj
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December 16th, 2010 at 4:39:02 PM permalink
Then 18 is your average.

Ken
minnesotajoe
minnesotajoe
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December 19th, 2010 at 1:10:36 PM permalink
Quote: mrjjj

Then 18 is your average.



Yes. Very true!

A woman tried telling me that a roulette bettor would be better off playing the outside than the inside because, "The House Advantage higher on the inside".

I explained that the HA is 5.26% regardles of inside or outside (I ignored the 00 0 1 2 3 wager)

She looked confused. Then I said, "Lets say you bet 18$ on red. That's the same as betting 1$ on each of the red numbers. If you bet 18$ red and a red hits.. you will have 36$ total. If you bet 1$ on any inside number and it hits... you will have 36$ total. 35-1 plus your wager. Betting 10$ on 1-18 is the same as betting 0.55555$ on 1, 2, 3... 18"

Edit: In initial post, I wrote, "1, 2, 3,...36".. should be 18 since only betting the 1-18 bet.
FleaStiff
FleaStiff
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December 19th, 2010 at 1:31:52 PM permalink
>>>>>> Zero, I'm strictly a Red/Black... Even/Odd ... High/Low bettor.
>>>>Then 18 is your average.
>>Yes. Very true!
I never thought of it that way, but it does seem correct. I'm really taking an equal portion of 18 straight up bets.

Quote: minnesotajoe

She looked confused. Then I said, "Lets say you bet 18$ on red. That's the same as betting 1$ on each of the red numbers. If you bet 18$ red and a red hits.. you will have 36$ total. If you bet 1$ on any inside number and it hits... you will have 36$ total. 35-1 plus your wager. Betting 10$ on 1-18 is the same as betting 0.55555$ on 1, 2, 3... 36"

My turn to look confused.
kenarman
kenarman
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December 19th, 2010 at 2:06:15 PM permalink
I usually play 5 numbers, the 17 straight-up and the associated 4 splits. The splits can keep me in the game but I need the 17 to hit to make any money.
Be careful when you follow the masses, the M is sometimes silent.
Martin
Martin
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December 19th, 2010 at 2:15:42 PM permalink
Quote: mrjjj

Then 18 is your average.

Ken



So it is.

My favorite way of playing is betting that the last color, or side (H/L) or type (O/E) will come again and then playing a mini-martingale until it does. I don't make a lot but I don't lose a lot either.

What is your "decent method?"
minnesotajoe
minnesotajoe
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December 19th, 2010 at 2:40:51 PM permalink
Don't be confused. If an average person that lacks above average math skills takes a quick glance, they will see... I have 1 in 38 shot at winning inside.. but outside is pretty much 50/50... I'm going to be smart and only bet outside.

Think of it like this.

If you bet 10$ on red. You have 18 winners. And 20 losers. So expected loss is 20$ for every 380$ you bet... which equals 0.0526
If you bet 10$ on any individual number. There 1 winner. 37 losers. You win 350$ lose 370$. Expected loss is 20$ for every 380$ bet... which is the same as outside
mrjjj
mrjjj
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December 19th, 2010 at 2:45:08 PM permalink
"What is your "decent method?" >>> Do you mean a definition?

Ken
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