December 15th, 2010 at 7:12:32 PM
permalink
This is a bit of a tough question. I'm wondering what your AVERAGE is per spin, how many numbers bet? I understand it might depend on what method you are playing etc. but try and post an average if you could. There is no wrong answer guys.
Thanks, Ken
Thanks, Ken
December 16th, 2010 at 12:41:39 PM
permalink
My average is 0 - I am an outside bettor exclusively - red/black, high/low, even/odd.
December 16th, 2010 at 4:39:02 PM
permalink
Then 18 is your average.
Ken
Ken
December 19th, 2010 at 1:10:36 PM
permalink
Quote: mrjjjThen 18 is your average.
Yes. Very true!
A woman tried telling me that a roulette bettor would be better off playing the outside than the inside because, "The House Advantage higher on the inside".
I explained that the HA is 5.26% regardles of inside or outside (I ignored the 00 0 1 2 3 wager)
She looked confused. Then I said, "Lets say you bet 18$ on red. That's the same as betting 1$ on each of the red numbers. If you bet 18$ red and a red hits.. you will have 36$ total. If you bet 1$ on any inside number and it hits... you will have 36$ total. 35-1 plus your wager. Betting 10$ on 1-18 is the same as betting 0.55555$ on 1, 2, 3... 18"
Edit: In initial post, I wrote, "1, 2, 3,...36".. should be 18 since only betting the 1-18 bet.
December 19th, 2010 at 1:31:52 PM
permalink
>>>>>> Zero, I'm strictly a Red/Black... Even/Odd ... High/Low bettor.
>>>>Then 18 is your average.
>>Yes. Very true!
I never thought of it that way, but it does seem correct. I'm really taking an equal portion of 18 straight up bets.
>>>>Then 18 is your average.
>>Yes. Very true!
I never thought of it that way, but it does seem correct. I'm really taking an equal portion of 18 straight up bets.
My turn to look confused.Quote: minnesotajoeShe looked confused. Then I said, "Lets say you bet 18$ on red. That's the same as betting 1$ on each of the red numbers. If you bet 18$ red and a red hits.. you will have 36$ total. If you bet 1$ on any inside number and it hits... you will have 36$ total. 35-1 plus your wager. Betting 10$ on 1-18 is the same as betting 0.55555$ on 1, 2, 3... 36"
December 19th, 2010 at 2:06:15 PM
permalink
I usually play 5 numbers, the 17 straight-up and the associated 4 splits. The splits can keep me in the game but I need the 17 to hit to make any money.
Be careful when you follow the masses, the M is sometimes silent.
December 19th, 2010 at 2:15:42 PM
permalink
Quote: mrjjjThen 18 is your average.
Ken
So it is.
My favorite way of playing is betting that the last color, or side (H/L) or type (O/E) will come again and then playing a mini-martingale until it does. I don't make a lot but I don't lose a lot either.
What is your "decent method?"
December 19th, 2010 at 2:40:51 PM
permalink
Don't be confused. If an average person that lacks above average math skills takes a quick glance, they will see... I have 1 in 38 shot at winning inside.. but outside is pretty much 50/50... I'm going to be smart and only bet outside.
Think of it like this.
If you bet 10$ on red. You have 18 winners. And 20 losers. So expected loss is 20$ for every 380$ you bet... which equals 0.0526
If you bet 10$ on any individual number. There 1 winner. 37 losers. You win 350$ lose 370$. Expected loss is 20$ for every 380$ bet... which is the same as outside
Think of it like this.
If you bet 10$ on red. You have 18 winners. And 20 losers. So expected loss is 20$ for every 380$ you bet... which equals 0.0526
If you bet 10$ on any individual number. There 1 winner. 37 losers. You win 350$ lose 370$. Expected loss is 20$ for every 380$ bet... which is the same as outside