November 17th, 2010 at 10:19:00 PM
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so u have two unique numbers lets just say 1 and two what is the probaility that one of those numbers will come up 3 spins in a row and if possible maybe four spins like as in 1 in 1000 or whatever
November 18th, 2010 at 11:22:20 AM
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I'm sorry, but I'm still having a difficult time understanding exactly what you're asking. I think it is because of your "3 spins in a row" terminology. I think you are asking this:
a) I select two numbers. For example, 1 and 2.
b) I spin the wheel three times (or four).
c) What is the probability that all three of these spins result in the same number, and its one of the two numbers that I picked.
So if the numbers are 1 and 2, the successful outcomes are 1/1/1 and 2/2/2. Any other outcome is a failure.
If I got this right, the answer is...
Assuming a European wheel...
The probability that the first spin is one of your two numbers is 2/37. The probability that the second spin is the same number as the first is 1/37. The probability that the third number is the same as the first two (given that the first two were the same) is 1/37. So the probability that all three numbers are the same, and also one of the two numbers you selected, is
2/37 x 1/37 x 1/37 = 0.00395%. This is about 1 in 25,000.
For four spins, the answer is 1 in 937,000.
a) I select two numbers. For example, 1 and 2.
b) I spin the wheel three times (or four).
c) What is the probability that all three of these spins result in the same number, and its one of the two numbers that I picked.
So if the numbers are 1 and 2, the successful outcomes are 1/1/1 and 2/2/2. Any other outcome is a failure.
If I got this right, the answer is...
Assuming a European wheel...
The probability that the first spin is one of your two numbers is 2/37. The probability that the second spin is the same number as the first is 1/37. The probability that the third number is the same as the first two (given that the first two were the same) is 1/37. So the probability that all three numbers are the same, and also one of the two numbers you selected, is
2/37 x 1/37 x 1/37 = 0.00395%. This is about 1 in 25,000.
For four spins, the answer is 1 in 937,000.
November 18th, 2010 at 11:56:48 AM
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as long as it is 1 of the two numbers that are picked is what i am asking so if u spin the wheel and i use the numbers 1 or 2 as long as on all three spins it one of those two numbers dont matter which one it could go 2/1/2, 1/1/1/, 2/2/2, 1/2/1 or any varation of such numbers as long as they pop up in the spins three and four spins are what i am curious about
November 18th, 2010 at 12:00:23 PM
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Quote: atrainas long as it is 1 of the two numbers that are picked is what i am asking so if u spin the wheel and i use the numbers 1 or 2 as long as on all three spins it one of those two numbers dont matter which one it could go 2/1/2, 1/1/1/, 2/2/2, 1/2/1 or any varation of such numbers as long as they pop up in the spins three and four spins are what i am curious about
(2/37)^3 for 3 spins, (2/37)^4 for four spins etc.
"When two people always agree one of them is unnecessary"