Please help with Roulette odds

I am trying to understand the odds in Roulette and would like help with calculations on betting in groups.

I like to play in groups of "6" on the side. I play 6 numbers (Usually splitting the 24's) in half.

I start with the last number hit. The play that group of 6. If I lose I add the next 6.

Example:
20 was rolled
I play 19 - 24
6 is rolled
I add 1-6 (12 total numbers)
33 is rolled
I add 31-36 (18 total numbers)
NOTE: I add 0 and 00 here for a total of 20 numbers

Can someone tell me the odds of winning on each section?

Round 1 6 of 38
Round 2 12 0f 38
Round 3 20 of 38
Round 4 26 of 38
Round 5 32 of 38

I'm also looking for the odds of going through all 5 rounds without hitting a number?

Thanks in advance for any help I can get.

Do you actually want the odds of winning each section? That answer seems too easy. The odds of winning when something happens 6/38ths of the time are 6/38...

Do you want the conditional probabilities of winning each section? if so, that's 6/38, then 32/28*12/38, then 32/38*26/38*20/38... To get the odds of going through al 5 rounds without winning, just multiply the probabilities of not winning each round (32/38*26/38*18/38*12/38*6/38)

You basically have your odds of hitting on each round... So what are the odds of not hitting on every round? The inverse multiplied together...

Odds of hitting:
1 - 6/38
2 - 12/38
3 - 20/38
4 - 26/38
5 - 32/38

So your odds of not hitting would be the remainders:
1 - 32/38 = .8421
2 - 26/38 = .6842
3 - 18/38 = .4737
4 - 12/38 = .3158
5 - 6/38 = .1579

The odds you don't hit 1 AND 2 AND 3 AND 4 AND 5... (when you use the word AND it's multiplication of the probabilities... when OR it's additive).

P(no hit 5 rounds) = P(no hit 1) * P(no hit 2) * P(no hit 3) * P(no hit 4) * P(no hit 5) = (32/38)*(26/38)*(18/38)*(12/38)*(6/38) = .0136, or about 1.36%.

Don't trick yourself in to thinking this is a winning proposition though... Each and every single bet carries a negative expectation to it.