Bowl Pick Em---No Spread
December 20th, 2014 at 8:51:03 AM
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I was just wondering, if there is a way to calculate or what the calculated expected win % would be for a bowl pick em with no spreads???
I understand with the spread the winner would normally be around 50% or a little better. I do realize that in cases such as the Wizards run in the NFL Pick Em contest, you can be much better than 50%, but on average 50% is where the majority of most would be. That is WITH spreads of course.
So straight up, no spread, where would the winner be expected to finish? My best guess is closer to 75%. Is this correct?
I understand with the spread the winner would normally be around 50% or a little better. I do realize that in cases such as the Wizards run in the NFL Pick Em contest, you can be much better than 50%, but on average 50% is where the majority of most would be. That is WITH spreads of course.
So straight up, no spread, where would the winner be expected to finish? My best guess is closer to 75%. Is this correct?
