Odds on quads in three different hands in 8 hours of live play?

What are the odds of losing to quads three times in eight hours of live play? Quads are 1/4200 approximately. How did this happen to me, especially when I hit full houses on the flop twice. Just a series of bad beats?

How many of your other quads won during that time?

Assuming that you didn't get another four of a kind during that time. The chances of losing three of the four of a kinds you received at a ten hand Texas Hold'em table in-a-row is about 1 chance in 81. The chance of a single four of a kind losing (without knowing anything else about the quality of the 4oak) is a little better than one in nine. so to lose two in a row, you have to lose the first one so that's a given, then one in nine times the third which is another one in nine.

1/81-ish

D'oh! I misread this. I think he was asking how many times does a 4oak come up in live play. And the answer is something like a %50 chance per 42 hands at a 10 player table. Assuming that you can churn out 42 hands per hour, that would be about a %50 chance per hour. Here's the logic:

That chance of a single hand being a 4oak is about 1 in 600.
The chances of not seeing a 4oak in a single deal at a 10 player table is (599/600)^10 = 0.983454
The chances of not seeing a 4oak in 42 deals at a 10 player table is 0.983454^42 = 0.496215

This of course assumes that all player play every hand through the river but when you're holding a pair as your hole cards, chances are pretty good you're going to pay to see the flop.

I don't think that seeing three 4oaks in 8 hours is an unreasonable expectation. Having two full houses that get beat by those 4oaks is just bad luck.