rdsandy
Joined: Jan 9, 2020
• Posts: 1
January 9th, 2020 at 2:04:52 PM permalink
I ran across a trips pay table, that would yield ~6% to the player assuming the bet is paid regardless of whether you beat the dealer or not. The Trips pay tables on the Wizard of Odds, assumes the bet wins regardless of whether the dealer beats you or not. Can someone figure out the trips bet advantage/disadvantage when the bet can only win if it beats the dealer.

Here is pay table #1 from the WOO website:

Player hand Combinations Pays Probability Return
Royal flush 4324 50 0.000032 0.001616
Straight Flush 37260 40 0.000279 0.01114
Quads 224848 30 0.001681 0.05042
Full House 3473184 9 0.025961 0.233649
Flush 4047644 7 0.030255 0.211785
Straight 6180020 4 0.046194 0.184775
Trips 6461620 3 0.048299 0.144896
All other 113355660 -1 0.8473 -0.8473
Total 133784560 1 -0.009018

How would the -.009018 change if the player has to beat the dealer to win the bet?

Here is the pay table I saw at the local card room:

Player hand Combinations Pays Probability Return
Royal flush 4324 100 0.000032 0.003232
Straight Flush 37260 50 0.000279 0.013925
Quads 224848 40 0.001681 0.067227
Full House 3473184 10 0.025961 0.25961
Flush 4047644 8 0.030255 0.24204
Straight 6180020 4 0.046194 0.184775
Trips 6461620 3 0.048299 0.144896
All other 113355660 -1 0.8473 -0.8473
Total 133784560 1 0.068405

The 0.068405 assumes a win even if you don't beat the dealer.

The actual table only pays if you beat the dealer.
What is the number if the player has to beat the dealer to win the bet?