April 24th, 2016 at 6:40:08 PM
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Assume the other guy had a pair of ace, + 2 other cards.
To make things simple, lets ignore sets, trips, straights, or flush etc. The way you can win is hope that the board will pair 2 of your 4 cards AND that there is no pair in the board. Lets also assume cards in your hand don't match any of his other 2.
Roughly speaking, what is the odd of that?
To make things simple, lets ignore sets, trips, straights, or flush etc. The way you can win is hope that the board will pair 2 of your 4 cards AND that there is no pair in the board. Lets also assume cards in your hand don't match any of his other 2.
Roughly speaking, what is the odd of that?
April 26th, 2016 at 7:04:38 AM
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Play with this... http://www.cardplayer.com/poker-tools/odds-calculator/omaha
You can set the hands and the board cards if you want and see the odds of each hand winning.
Off the top... if you opponent has A-A-x-x and you have 4 cards all different, you're about a 60/40.
You can set the hands and the board cards if you want and see the odds of each hand winning.
Off the top... if you opponent has A-A-x-x and you have 4 cards all different, you're about a 60/40.
Playing it correctly means you've already won.