November 13th, 2026 at 9:35:06 AM
permalink
Every Roulette Strategy, Tested on 10 Billion Spins - Dice Lab - 267 subscribers
https://www.youtube.com/watch?v=ds_IN1OWgoQ
Double after every loss. Bet against the streak. Always red. Spread your chips like James Bond. Quit while you're ahead. Every roulette player has a system, so I built a roulette wheel in code, gave 13 players $1,000 and a $10 chip each, and let each one play 650,000 nights.
The players: Flat Red, Lucky Number (17), Hot Number, Martingale, Fibonacci, D'Alembert, Labouchère, Paroli, James Bond, Streak Hunter, Two Dozens, Bold Play (all-in once) and Random.
What came out:
Every system lost 2.7% of what it bet: 2.66% to 2.75%, the house edge of a single-zero wheel. Systems change how you lose, not how much.
The Martingale with a $10 million bankroll finished ahead on 99.4% of nights and still lost $1,021 per night on average. With a $1,000 table limit it won only 58.5% of nights.
James Bond finished last: $436 left on average, broke on 86% of nights. He bets $200 a spin.
After 5, 10 or 15 reds in a row, red came up again 48.6% of the time. Nothing is ever "due". The longest run in one billion spins was 27.
To turn $1,000 into $2,000: $10 bets get there 0.5% of the time, the Martingale 41.5%, and one all-in bet on red 48.6% (Dubins & Savage, "How to Gamble If You Must", 1965).
$1,000 at $10 on red lasts 3,692 spins on average, and you bet about $37,000 to lose it. The Martingale lasts ~1,011 spins and also bets ~$37,000.
An American double-zero wheel doubles the edge to 5.26%; La Partage halves it to 1.35% on even-money bets.
A wheel where 17 comes up 1 in 33 instead of 1 in 37 beats the house, but you'd need about 37,000 spins of notes to find it 94% of the time.
How it was tested: European wheel (37 pockets) unless stated, $1,000 bankroll, $10 base bet, $1,000 table maximum, 300-spin nights. 10,194,939,584 spins in total, including a one-billion-spin streak test and a biased-wheel test.
https://www.youtube.com/watch?v=ds_IN1OWgoQ
Double after every loss. Bet against the streak. Always red. Spread your chips like James Bond. Quit while you're ahead. Every roulette player has a system, so I built a roulette wheel in code, gave 13 players $1,000 and a $10 chip each, and let each one play 650,000 nights.
The players: Flat Red, Lucky Number (17), Hot Number, Martingale, Fibonacci, D'Alembert, Labouchère, Paroli, James Bond, Streak Hunter, Two Dozens, Bold Play (all-in once) and Random.
What came out:
Every system lost 2.7% of what it bet: 2.66% to 2.75%, the house edge of a single-zero wheel. Systems change how you lose, not how much.
The Martingale with a $10 million bankroll finished ahead on 99.4% of nights and still lost $1,021 per night on average. With a $1,000 table limit it won only 58.5% of nights.
James Bond finished last: $436 left on average, broke on 86% of nights. He bets $200 a spin.
After 5, 10 or 15 reds in a row, red came up again 48.6% of the time. Nothing is ever "due". The longest run in one billion spins was 27.
To turn $1,000 into $2,000: $10 bets get there 0.5% of the time, the Martingale 41.5%, and one all-in bet on red 48.6% (Dubins & Savage, "How to Gamble If You Must", 1965).
$1,000 at $10 on red lasts 3,692 spins on average, and you bet about $37,000 to lose it. The Martingale lasts ~1,011 spins and also bets ~$37,000.
An American double-zero wheel doubles the edge to 5.26%; La Partage halves it to 1.35% on even-money bets.
A wheel where 17 comes up 1 in 33 instead of 1 in 37 beats the house, but you'd need about 37,000 spins of notes to find it 94% of the time.
How it was tested: European wheel (37 pockets) unless stated, $1,000 bankroll, $10 base bet, $1,000 table maximum, 300-spin nights. 10,194,939,584 spins in total, including a one-billion-spin streak test and a biased-wheel test.

