Difference between 3to2 and 6to5 in spanish21
March 21st, 2014 at 2:37:09 PM
permalink
Hi,
I'm wondering what the difference is in the house edge in spanish21 between 3to2 and 6to5?
I'm wondering what the difference is in the house edge in spanish21 between 3to2 and 6to5?
March 21st, 2014 at 10:37:17 PM
permalink
Which part of the calculation are you having trouble with?
March 22nd, 2014 at 12:18:25 AM
permalink
Calculate the probability that the player will get a natural (while the dealer has not), then reduce the payout to 6:5. This will gives you the increase in house edge.
March 23rd, 2014 at 4:07:16 PM
permalink
Quote: MangoJCalculate the probability that the player will get a natural (while the dealer has not), then reduce the payout to 6:5. This will gives you the increase in house edge.
Fixed that for you. In Spanish 21, player blackjacks win even if a dealer has a blackjack.
Casinos are not your friends, they want your money. But so does Disneyland.
And there is no chance in hell that you will go to Disneyland and come back with more money than you went with.
- AxelWolf and Mickeycrimm
March 24th, 2014 at 5:47:51 AM
permalink
If I were trying to figure out the difference in house edge, although this may not be correct, but the way I'd think of it....figure out the probability of hitting a blackjack then subtract 3/10'th of the bet. 3:2 is 15:10 and 6:5 is 12:10, 15:10-12:10 = 3/10. Every time you hit a BJ, you're losing $30!! [on a $100 bet].
Roughly speaking, and this is an EXAMPLE (ie: i don't know what 3:2 or 6:5 house edges are), but let's say you expect to hit 1 blackjack every 20 hands (I think it's more like 21 or 19 hands, but w/e), on a 3:2 and the HE is 0.5%. You'd figure that every $100 wager (at -0.5%) means you're losing $0.50/hand After 20 hands, you're losing $10. That's based on a 0.5% HE. But then calculate in the fact that you're also losing an extra $30 every time you hit a blackjack (instead of getting paid $150, you're getting paid $120). Since you expect 1 BJ every 20 hands, and every BJ you get means you're losing $30...........you lose $30 every 20 hands for BJ's and $10 every 20 hands based on 0.5% HE, for a net of -$40/20 hands. 20 hands of $100 = $2,000 in action. 40/2,000 = 2%...so the new house edge would be 2% Then again, that's with very rounded and made-up figures (well, the only made-up figures is the 0.5% house edge and the 1 BJ per 20 hands).
Another way to do it, basically the same just a little different, is figure the probabilty of getting a blackjack. If the probability of getting a BJ is 5% (congruent with 1 BJ per 20 hands), then 5% of the time you're losing $30 (because you're getting paid $120 instead of $150 on a $100 BJ). After 100 hands of $100 each, for a total action of $10,000. 100(hands) * 0.05 (5% BJ's) * -30 (loss on a BJ) = -$150, so that's your loss on JUST BJ's. Also factor in the HE which is 0.5%, so 10000*-0.005 = -$50. Add the two losses together and you get -$200 per 100 hands. Which is the same as losing $2 per hand. $2 per hand at $100 is 2%....which is the same as above. Used the same figures (0.5% HE, 1 BJ per 20 hands, $100 unit).
Perhaps there are other things I did not consider, since I don't play the game I don't know them...but if there are different payouts for different kinds of BJ's (suited BJ pay different? Ace-King pay different? Or only Suited Ace-King? etc.). Figure the probablity of hitting a BJ compared to the payout, subtract the payout from the actual return of the game, and voila, new house edge.
Roughly speaking, and this is an EXAMPLE (ie: i don't know what 3:2 or 6:5 house edges are), but let's say you expect to hit 1 blackjack every 20 hands (I think it's more like 21 or 19 hands, but w/e), on a 3:2 and the HE is 0.5%. You'd figure that every $100 wager (at -0.5%) means you're losing $0.50/hand After 20 hands, you're losing $10. That's based on a 0.5% HE. But then calculate in the fact that you're also losing an extra $30 every time you hit a blackjack (instead of getting paid $150, you're getting paid $120). Since you expect 1 BJ every 20 hands, and every BJ you get means you're losing $30...........you lose $30 every 20 hands for BJ's and $10 every 20 hands based on 0.5% HE, for a net of -$40/20 hands. 20 hands of $100 = $2,000 in action. 40/2,000 = 2%...so the new house edge would be 2% Then again, that's with very rounded and made-up figures (well, the only made-up figures is the 0.5% house edge and the 1 BJ per 20 hands).
Another way to do it, basically the same just a little different, is figure the probabilty of getting a blackjack. If the probability of getting a BJ is 5% (congruent with 1 BJ per 20 hands), then 5% of the time you're losing $30 (because you're getting paid $120 instead of $150 on a $100 BJ). After 100 hands of $100 each, for a total action of $10,000. 100(hands) * 0.05 (5% BJ's) * -30 (loss on a BJ) = -$150, so that's your loss on JUST BJ's. Also factor in the HE which is 0.5%, so 10000*-0.005 = -$50. Add the two losses together and you get -$200 per 100 hands. Which is the same as losing $2 per hand. $2 per hand at $100 is 2%....which is the same as above. Used the same figures (0.5% HE, 1 BJ per 20 hands, $100 unit).
Perhaps there are other things I did not consider, since I don't play the game I don't know them...but if there are different payouts for different kinds of BJ's (suited BJ pay different? Ace-King pay different? Or only Suited Ace-King? etc.). Figure the probablity of hitting a BJ compared to the payout, subtract the payout from the actual return of the game, and voila, new house edge.
