Betting by multiples of 2
December 7th, 2014 at 9:51:30 AM
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I have been following this site for awhile and realize betting systems are worthless but I would like to ask the community if they had tried this system and have gotten any luck.
By multiples of 2 I mean betting on the pass or dont only with a base bet.
If the minimum bet is $3 the betting formula would be: 3, 6, 12, 24, 48, 96, 192
If the minimum bet is $5 the betting formula would be: 5, 10, 20, 40, 80, 160, 320
Assuming your bank roll is sufficient enough to maintain this, What are the chances of missing 7 in a row with this method betting on only the pass and don't pass? Is this too risky?
Edit: This may be in the wrong section, I am new to the forum and don't know how to move it to the betting system section.
By multiples of 2 I mean betting on the pass or dont only with a base bet.
If the minimum bet is $3 the betting formula would be: 3, 6, 12, 24, 48, 96, 192
If the minimum bet is $5 the betting formula would be: 5, 10, 20, 40, 80, 160, 320
Assuming your bank roll is sufficient enough to maintain this, What are the chances of missing 7 in a row with this method betting on only the pass and don't pass? Is this too risky?
Edit: This may be in the wrong section, I am new to the forum and don't know how to move it to the betting system section.
December 7th, 2014 at 10:36:49 AM
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Smells like a Martingale, but not quite. Your chances of losing 7 decisions in a row is .495^7 (roughly 0.00728176053 or 7 times in a thousand; I make no claim to be a mathematician), but it is possible. Your bankroll would need to be sufficient to sustain double your largest loss, and you would likely bump into table limits if you started with a higher base bet or if the streak went on for 9 or 10 events.
If government is the answer, it must have been a very stupid question.
December 7th, 2014 at 10:39:01 AM
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And so it beginsQuote: infilI have been following this site for awhile and realize betting systems are worthless but..
♪♪Now you swear and kick and beg us That you're not a gamblin' man Then you find you're back in Vegas With a handle in your hand♪♪ Your black cards can make you money So you hide them when you're able In the land of casinos and money You must put them on the table♪♪ You go back Jack do it again roulette wheels turinin' 'round and 'round♪♪ You go back Jack do it again♪♪
December 7th, 2014 at 10:45:05 AM
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If you win before 7 losses in a row, the amount of your win minus the amount of your losses always equals your initial bet. On the other hand, if you lose 7 in a row, the total losses equals 127 times your bet. The probability of losing 7 in a row is about 1 in 116.
What you are doing is, you are letting the casino bet on an event that has a probability of 1/116, but it pays 127-1. Who do you think has the advantage? (And no, the casino's advantage does not go down if you increase the number of losses allowed.)
What you are doing is, you are letting the casino bet on an event that has a probability of 1/116, but it pays 127-1. Who do you think has the advantage? (And no, the casino's advantage does not go down if you increase the number of losses allowed.)
December 7th, 2014 at 4:29:38 PM
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Quote: ThatDonGuy
What you are doing is, you are letting the casino bet on an event that has a probability of 1/116, but it pays 127-1. Who do you think has the advantage? (And no, the casino's advantage does not go down if you increase the number of losses allowed.)
The casino?
