https://wizardofodds.com/games/blackjack/rule-variations/
I have a question as it relates to the percentages, plus and minus, within this table.
For example, the first variance listed on the chart is paying 2:1 on BJ versus 3:2 . It states that by doing this, it has a +2.27% net effect for the player. Does that mean that, if no other variance was incorporated, that the overall house edge is +2.27% for the player? Or, that the player's chances of winning have merely increased by 2.27%?
Quote: RivaIn another thread, we had a lively conversation surrounding the house taking ties in BJ played at charitable games. In that thread, someone posted this link to the effect of house edge based on variations or the rules.
https://wizardofodds.com/games/blackjack/rule-variations/
I have a question as it relates to the percentages, plus and minus, within this table.
For example, the first variance listed on the chart is paying 2:1 on BJ versus 3:2 . It states that by doing this, it has a +2.27% net effect for the player. Does that mean that, if no other variance was incorporated, that the overall house edge is +2.27% for the player? Or, that the player's chances of winning have merely increased by 2.27%?
My understanding is that the chart separates out each choice as an independent variable, and is like a chinese menu; pick one from group A, one from group B, and so on. So Group A: BJ pays 6:5 does one thing, BJ 3:2 does another, BJ 2:1 a third, BJ 7:5 a fourth. In the lead-in paragraph, Wiz does not mention this, but standard BJ is 3:2 on wins, so that's the +0.00 point. In isolation, BJ 2:1 pays +2.27% better for the player than that. Using the lead-in paragraph as the 0.00 point rules, the table goes from that standard with + or - EV from the POV of the player.
Quote: RivaFor example, the first variance listed on the chart is paying 2:1 on BJ versus 3:2 . It states that by doing this, it has a +2.27% net effect for the player. Does that mean that, if no other variance was incorporated, that the overall house edge is +2.27% for the player?
No. The HE switches from what it was (say X) to X+0.0227.
Or, that the player's chances of winning have merely increased by 2.27%?
No. HE is an expectation (a mean value), not a probability.