couple of card counting assumptions need all of your opinions

if you count dealer's cards only, in the long run it's going to be or at least close to zero.
if you count your own cards only, in the long run it's going to be or at least close to zero.

any1 know if its true or false to these 2 assumptions?

if it's true, the next question will be how the counts gonna affect house/player's edge?

assuming continuous are good, yes.

Counting a subset of cards will average the same count as counting every card. For the hi/lo count...that's 0. But only counting a subset of cards (like the dealer's cards only) will be much less effective overall though because the true count will only be based on the number of cards you have seen from the dealer. For example, if you have seen 52 dealer cards dealt with a running count of +5...then the true count would only be +1 with a 6-deck shoe since you have no idea about the rest of the cards dealt and by that point the shoe will be nearly exhausted.

my theory is based on playing against continuous shuffle machine. i "assume" if i sit in a table counting dealer's cards and my own cards all day, both of the counts is going to be or at least close to zero.

and if my assumption is true then knowing dealer's count and my count would give us the edge of winning right?
for example, if the dealer's count is +10 and my count is +10 at some point.
dealer got a 3 and i got a 13. according to basic strategy i should hit but by knowing the count i might go for stand instead.

Quote: TBsp75

my theory is based on playing against continuous shuffle machine. i "assume" if i sit in a table counting dealer's cards and my own cards all day, both of the counts is going to be or at least close to zero.

and if my assumption is true then knowing dealer's count and my count would give us the edge of winning right?
for example, if the dealer's count is +10 and my count is +10 at some point.
dealer got a 3 and i got a 13. according to basic strategy i should hit but by knowing the count i might go for stand instead.

Good Luck

If I'm going to go that far, I might as well estimate.

Quote: TBsp75

if you count dealer's cards only, in the long run it's going to be or at least close to zero.
if you count your own cards only, in the long run it's going to be or at least close to zero.

any1 know if its true or false to these 2 assumptions?

if it's true, the next question will be how the counts gonna affect house/player's edge?

This sounds likely enough, but honestly I don't know if I could agree with the first assumption. A dealer stands on two high cards, like Ten-Ten, Ace-King, even Ace or Ten with neutral cards, but always hits with two low cards (Two-Six) and the card they draw has an equal chance of being "high" or "low". Also, the dealer hits with a low and neutral card vs stays with a high and neutral card (hits on 2,9; stands on King,9).

Probably in the end the cards drawn would even it out, I'm just saying it involves a little more thought.