## Poll

17 votes (60.71%) | |||

3 votes (10.71%) | |||

8 votes (28.57%) |

**28 members have voted**

Quote:heatherThere are at least two online casinos that have been running that exact promotion for a few years now. Must be working out okay for them, because they're still doing it.

The only ones I heard of with such promotions, were, I think, charging a commission either on bets or on winnings on those "zero-house-edge" games, effectively, no only negating the value of the promotion, but actually making it worse than the regular game. Ah, greed ...

Quote:weaselmanYeah ... I stand corrected. I was thinking about one player playing against casino, and still not having a very good shot at finishing ahead. On average over all the players, the casino will not be winning.

This is a remarkable post! A forum member made a post which was factually incorrect, then read a subsequent post, and changed his mind! Congrats, weaselman! It hurts my brain when someone says the casino will eventually make money on true even money bets.....

Quote:heatherThere are at least two online casinos that have been running that exact promotion for a few years now. Must be working out okay for them, because they're still doing it.

It might be working out for them for a few different possible reasons....

1. They cheat the players, and if they set the game to pay 99% no player would probably ever know........

2. They make money on deposit charges and withdrawal fees...

3. Although neither winning nor losing money on this game, players might wander to other games the online casino offers...

Quote:thecesspit

Of those gamblers, 16787 busted. Only 1011 made a profit,

Take it to the end. Give the 1011 players another 100,000

spins. Then give those winners another 100K. Till there are

no winners left. Just for fun.

equal the even bets, the it would favor the house

for this reason. If you carry R/B, for instance, into

infinity, not only are they never equal, they become

farther apart as time goes on.

You'll find after 10m spins, R/B are thousands of

spins apart. After 20m spins, they are even farther

apart. And so on. And this would favor the player

with the largest BR, which is always the casino.

Quote:EvenBobIt seems to me that because all bets in roulette

equal the even bets, the it would favor the house

for this reason. If you carry R/B, for instance, into

infinity, not only are they never equal, they become

farther apart as time goes on.

You'll find after 10m spins, R/B are thousands of

spins apart. After 20m spins, they are even farther

apart. And so on. And this would favor the player

with the largest BR, which is always the casino.

This is a mixture of true, misleading, and false. The R/B count at some time in the future will be equal, with probability ~1. The R/B difference follows a random walk. The largest magnitude of difference does increase over time, but there will be periods when they are very close or equal.

A casino will wipe out one player in an even game, but not all players. The other posters are correct.

silly

Sally

Quote:dwheatleyThe R/B count at some time in the future will be equal,

Nope, they won't. Statistically they will be closer, like

99.9997% instead of 99.9996%. But physically,

actually, they will continue to be farther apart. Forever. I'm

not making this up, do a sim. Its a fact.

I agree with dwheatleyQuote:EvenBobNope, they won't. Statistically they will be closer, like

99.9997% instead of 99.9996%. But physically,

actually, they will continue to be farther apart. Forever. I'm

not making this up, do a sim. Its a fact.

You need to go back to your random walk studies and read more on "Passage times"

(you are correct when p does not equal q)

"If p = q we get

(formula left out)

by Theorem 2.

Remark 3.

The symmetric random walk will therefore, with probability 1, return to 0. This

holds after each return, so that

P(Sn = 0 i.o.) = 1.

Although the walk will return to zero infinitely often,

the expected time between returns is infinite!

The law of large numbers can therefore not be interpreted as saying that the particle usually is close

to 0. In fact, the particle is rarely close to 0 and a large proportion of the time is spent far away

from 0, even in a symmetric random walk!"

Now, back to the topic of this thread.

I say, no, today, card counting does not work.

If a player thinks it does, they have just not played enough hands and are just on the positive side of variance.

If it was true, over 100 million players would be killing the casinos with their BJ play.

That is not happening.