AverageJOE
Joined: Sep 27, 2010
• Posts: 124
September 12th, 2011 at 5:18:44 AM permalink
I don't use or play systems - but i woundering what the probability is regarding following senario.

1. If there exist a dice with 8 sides - then what is the probability that it alternating - that every side have one show each during 8 times ?

2. If there exist a dice with 8 sides - then what is the probability that the dice repeat one side 8 times ?

Cheers
AP - It's not that it can't be done, but rather people don't really have a clue as to the level of fanaticism and outright obsession that it takes to be successful, let alone get to the level where you can take money out of the casinos on a regular basis. Out of 1,000 people that earnestly try, maybe only one will make it.
AverageJOE
Joined: Sep 27, 2010
• Posts: 124
September 12th, 2011 at 5:26:10 AM permalink
Quote: AverageJOE

I don't use or play systems - but i woundering what the probability is regarding following senario.

1. If there exist a dice with 8 sides - then what is the probability that it alternating - that every side have one show each during 8 times ?

2. If there exist a dice with 8 sides - then what is the probability that the dice repeat one side 8 times ?

Cheers

Is this correct measuring the standard division regarding one side with out one show during 8 times ?
I assume that the dice have 8 degree of freedom and are random - as roulette has 37/38 degree of freedom.

1. A - 0.00
2. B - 0.13
3. C - 0.36
4. D - 0.69
5. E - 1.10
6. F - 1.59
7. G - 2.14
8. H - 2.75

Cheers
AP - It's not that it can't be done, but rather people don't really have a clue as to the level of fanaticism and outright obsession that it takes to be successful, let alone get to the level where you can take money out of the casinos on a regular basis. Out of 1,000 people that earnestly try, maybe only one will make it.
Lucyjr
Joined: May 25, 2010
• Posts: 32
September 12th, 2011 at 5:35:53 AM permalink
The odds of your next 8 throws showing #s 1-8, in any order, are: 40,320/16,772,216 (approx 1 in 416 chance)

Odds of the next 8 throws all being the same # are: 8/16,772,216 (approx 1 in 2.1 million)
AverageJOE
Joined: Sep 27, 2010
• Posts: 124
September 12th, 2011 at 6:04:19 AM permalink
Quote: Lucyjr

The odds of your next 8 throws showing #s 1-8, in any order, are: 40,320/16,772,216 (approx 1 in 416 chance)

Odds of the next 8 throws all being the same # are: 8/16,772,216 (approx 1 in 2.1 million)

Thanks :-)

Now would it also be 1 in 2.1 milion if each side each repeat once during 16 times ?
Like AABBCCDDEEFFGGHH just curios ...

Many Thanks ...
AP - It's not that it can't be done, but rather people don't really have a clue as to the level of fanaticism and outright obsession that it takes to be successful, let alone get to the level where you can take money out of the casinos on a regular basis. Out of 1,000 people that earnestly try, maybe only one will make it.