Poker Math
May 5th, 2011 at 7:01:48 AM
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2 Players (A and B)
Each player holds 5 cards
Player A holds 4 aces and a 2 of hearts
Player B can beat the hand of Player A with a straight flush
How probable is the following event F: Player B has a straight flush
Pr[F] = |F| / |Ω| = (3 * 8 + 7) / ((52 - 5) over 5)= 31 / 1533939 = 2.02 * 10^(-5)
Is the above answer correct?
EDIT: the term ((52 - 5) over 5) should probably be combin((52 - 5), 5). I do not know the exact notation.
Each player holds 5 cards
Player A holds 4 aces and a 2 of hearts
Player B can beat the hand of Player A with a straight flush
How probable is the following event F: Player B has a straight flush
Pr[F] = |F| / |Ω| = (3 * 8 + 7) / ((52 - 5) over 5)= 31 / 1533939 = 2.02 * 10^(-5)
Is the above answer correct?
EDIT: the term ((52 - 5) over 5) should probably be combin((52 - 5), 5). I do not know the exact notation.
May 5th, 2011 at 7:21:24 AM
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With your edit, it looks good to me. This is actually the conditional probability Pr[F/A], where A is the fact that player A has that specific hand.
