December 6th, 2009 at 12:33:49 PM
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Playing blackjack heads-up against the dealer (6-8 decks, dealer hits soft 17, no surrender, re-split to 4 hands with doubling allowed after splitting, except aces which can be split once with a one card draw to each). What would be the expected frequency of the dealer winning 2, 3, 4, or 5 hands in a row, and losing 2, 3, 4, or 5 hands in a row (excluding pushes)?
December 6th, 2009 at 1:19:32 PM
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Assuming the dealer will win 47.9% of the time (43.3% player and 8.8% push), the odds are as follows:
2 in a row: 22.94%
3 in a row: 10.99%
4 in a row: 5.26%
5 in a row: 2.52%
X in a row: .479^X
2 in a row: 22.94%
3 in a row: 10.99%
4 in a row: 5.26%
5 in a row: 2.52%
X in a row: .479^X
December 7th, 2009 at 12:11:26 PM
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Quote: lucky13Assuming the dealer will win 47.9% of the time (43.3% player and 8.8% push), the odds are as follows:
2 in a row: 22.94%
3 in a row: 10.99%
4 in a row: 5.26%
5 in a row: 2.52%
X in a row: .479^X
If you are looking for the returns in Blackjack streaks...
https://wizardofodds.com/blackjack/appendix8.html#streak
The probability of winning n hands in a row is simply 0.4751n. The following return tables show the pay table, probability of winning, and return for all four streak bets, under both the new and old rules.
Streak Bet Return Table - New Rules
Streak
Bet Pays Probability
Win Return
2 3 0.225712 -0.097154
3 8 0.107234 -0.034898
4 18 0.050946 -0.032032
5 38 0.024204 -0.05605
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